you're definitely your best option with reference to the minimum potential... it extremely is on the floor after it has fallen the completed distance from its max height. There the completed potential TE = 0 because of fact KE = 0 and PE = 0, and after some seconds, QE = 0 besides. QE is the deformation, friction, and warmth potential because of end result. That dissipates over the years. yet, it extremely is substantial, whilst soliciting for the minimum potential in a trajectory, till now the end result, there is none. the completed potential TE maintains to be fastened throughout the time of the trajectory. in basic terms the content cloth of that entire potential differences from waypoint to waypoint. working example, at launch, TE = KE = a million/2 mV^2 the place V is the muzzle or launch speed. Then, on the max height H above the h = 0 height point (i.e., floor point), TE = KE = KEx + PE = a million/2 mVx^2 + mgH. So the completed kinetic potential TE = KE = a million/2 mV^2 = KEx + PE has been converted into KEx < KE and PE < KE at max height H. KEx is the minimum kinetic potential collectively as interior the trajectory. till now accomplishing max H, there's somewhat KEy, kinetic potential from the vertical speed Vy. After accomplishing max H, Vy comes back because of gravity container g. KEx maintains to be fastened because of fact, barring drag forces, Vx is continuous throughout the time of the trajectory. minimum pe = mgh = mg 0 = 0 (just about) in basic terms ahead of result at h just about 0. At this factor, TE = KE as quickly as back because of fact the completed potential is all kinetic. From the conservation of potential, we've KE = KEx + PE. it extremely is, the completed potential in basic terms ahead of result got here from changing the completed potential at max height H.