# calculation-heat

A man is drilling an iron block of 2.5 kg.The power of drill is 2500W.Suppose 60% of the power has been lost as heat and increases the temp. of the iron block.The S.H.C of iron is 470

(a)Find the temp. rise of block in 1 min.

ans:76.6

(b)If water is dripping into the hole at steady rate of 20g s^-1,find the temp. rise of block in 1 min.

ans:14.5

(c)Find the maximum temp. increase of the block if water is dripping into the hole at rate stated in (b).

ans:17.9

Only help me to do part (c)

### 1 Answer

- 天同Lv 71 decade agoBest Answer
(c) The heat gain by the dripping water in 1 sec

= (20/1000)x 4200 x T

where T is the rise in temperature of the water, and 4200 J/kg-K is the specific heat capacity of water

Heat generated by the drill = 2500 x 0.6 J/s

The temperature of the block will become steady when the heat generated is all taken away by the dripping water.

i.e. 2500x0.6 = (20/1000)x 4200 x T

solving for T gets T = 17.9 deg.C