STP help!!!!!!!!!?

.03246 mol NO in liters @ STP

how do you do that?

3 Answers

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  • 1 decade ago
    Favorite Answer

    At STP, 1 mole of any ideal gas occupies a volume of 22.4 Liters.

    For this problem, we will assume that Nitrogen Monoxide (NO) is an ideal gas.

    1 mol / 22.4 Liter = .03246 mol / x Liters

    Volume of NO gas = .03246 moles * 22.4 moles / Liter

    Volume = .727104 Liters

    Volume = .727 Liters

  • 1 decade ago

    Use the ideal gas law, PV = nRT, then work your way for the solution.

    P = pressure

    V = volume

    n = moles

    R = constant (with different units)

    T = temperature (in Kelvins)

  • Helmut
    Lv 7
    1 decade ago

    @ STP, any 1 mole of any gas occupies 22.4 liters, so 0.03246 moles occupies 0.03246*22.4 = 0.7271 liters.

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