.03246 mol NO in liters @ STP
how do you do that?
- mrjeffy321Lv 71 decade agoFavorite Answer
At STP, 1 mole of any ideal gas occupies a volume of 22.4 Liters.
For this problem, we will assume that Nitrogen Monoxide (NO) is an ideal gas.
1 mol / 22.4 Liter = .03246 mol / x Liters
Volume of NO gas = .03246 moles * 22.4 moles / Liter
Volume = .727104 Liters
Volume = .727 Liters
- 1 decade ago
Use the ideal gas law, PV = nRT, then work your way for the solution.
P = pressure
V = volume
n = moles
R = constant (with different units)
T = temperature (in Kelvins)
- HelmutLv 71 decade ago
@ STP, any 1 mole of any gas occupies 22.4 liters, so 0.03246 moles occupies 0.03246*22.4 = 0.7271 liters.