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# STP help!!!!!!!!!?

.03246 mol NO in liters @ STP

how do you do that?

### 3 Answers

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- mrjeffy321Lv 71 decade agoFavorite Answer
At STP, 1 mole of any ideal gas occupies a volume of 22.4 Liters.

For this problem, we will assume that Nitrogen Monoxide (NO) is an ideal gas.

1 mol / 22.4 Liter = .03246 mol / x Liters

Volume of NO gas = .03246 moles * 22.4 moles / Liter

Volume = .727104 Liters

Volume = .727 Liters

- 1 decade ago
Use the ideal gas law, PV = nRT, then work your way for the solution.

P = pressure

V = volume

n = moles

R = constant (with different units)

T = temperature (in Kelvins)

- HelmutLv 71 decade ago
@ STP, any 1 mole of any gas occupies 22.4 liters, so 0.03246 moles occupies 0.03246*22.4 = 0.7271 liters.

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