How many milliliters of 0.140 M HCl is need titrate this at equivalence point?
How many milliliters of 0.140 M HCl are needed to titrate each of the following solutions to the equivalence point?
(a) 40.0 mL of 0.0950 M NaOH
(b) 23.5 mL of 0.126 M KOH
(c) 125.0 mL of a solution that contains 1.20 g of NaOH per liter
beanie is right. except for B, which was simply a copy error. he/she was a decimal pt off.
- 1 decade agoFavorite Answer
convert all to moles
a) .0400L* 0.0950M = .0038 moles
b) .0235L * .0126M = .0002961
c) 1.20g/ 40gNaOH/ mole = 0.030 M *.1250L =0.00375 moles
how many moles/ L is there of the HCl (easy one) 0.140moles/ L
a) .0038 moles NaOH/ 0.140 moles HCl / L =0.0271 L or 27.1mL
b).0002961moles KOH/ 0.140 moles HCl / L = 0.00212L or 2.1mL
c) 0.00375 moles NaOH/ 0.140moles HCl/ L = 0.0268L or 26.8mL