Can you balance this chemical equation?

CH4(g) + O2 --> CO2(g) + H2O + energy

I was also wondering if the enery that is with the H20 makes any difference in balancing the equation. Thanks.

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• Anonymous

CH4(g) + 2O2 --> CO2(g)+2 H2O+ energy

i dont think that the energy doesn't do anything

CH4(g) + 2 O2 --> CO2(g) + 2 H2O + energy

the answer to ur other question....no, its not with the H2O, the energy is just another one of the products (everything to the right of the arrow)

• Anonymous

1 methane

2 water

1 carbon dioxide

2 oxygen

The energy involved won't change the coefficients you need to put in front of the chemicals involved in the equation.....

but.....

the energy you get when you burn 1 mole of methane is known as methane's "heat of combustion". There are cases (and I don't think you're there yet), where if you need to double or triple everything in an equation to calculate a heat of reaction, then the energy would also get doubled or tripled.

Source(s): I teach chemistry

Hi!

What I get is this:

CH4 + 2O2 --> CO2 + 2H2O + Energy

Well, I do not think that the energy has any affect.

I hope I helped and Happy New Year 2007!

CH4 +2 O2 --> CO2 +2 H2O + energy

L.H.S

C=1

H=4

O=4

R.H.S

C=1

H=4

O=4

yes but you would need to invoke nuclear synthesis :)

??(g)