3/y-6 - 1/6?

Simplify and the y-6 is all under the 3.

Thanks!

7 Answers

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  • 1 decade ago
    Favorite Answer

    First: determine the least common denominator > 6(y-6) > combine all the denominators.

    Second: multiply missing terms to each fraction (top and bottom) to get the LCD > 6(y - 6).

    [6(3)/6(y - 6)] - [1(y - 6)/6(y - 6)]

    18/6(y - 6) - (y - 6)/6(y - 6)

    Third: combine the numerators.

    [18 - (y - 6)]/6(y - 6)

    [18 - y + 6]/6(y - 6)

    24 - y/6(y - 6)

    *Its important to keep the numerator in alpha descending order:

    -y + 24/6(y - 6)

    Or y - 24/6(y - 6)

    Source(s): tutoring 4 yrs
  • Anonymous
    1 decade ago

    The common denominators are y-6 and 6:

    (3/y-6)/6(y-6)-(1/6)/6(y-6)

    (3(6)-(y-6))/6(y-6)

    (18-y+6)/6(y-6)

    24-y/6y-36 is the final answer!

  • 1 decade ago

    First, get the two to the same denominator (part underneath). To do that, the fastest way is to cross-multiply - multiply the 3/y-6 by 6/6 and the 1/6 by y-6/y-6. That gives you the same denominator and you can combine into one fraction.

    That gives (18)/(6(y-6) - (y-6)/(6(y-6))

    or (18 - (y-6)) / (6y-36)

    or (24 - y) /(6y-36)

  • 1 decade ago

    3/y-6 -1/6 solution: 18-(y-6)/y-6=0

    18-y-6=0

    -y= -18+6

    -y= -12,y=12

    nb:y-6 is under the 18-(y-6)

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  • 1 decade ago

    Common denominator is 6(y-6)

    3/(y-6) - 1/6 = 18/[6(y-6)] - [y-6]/[6(y-6)] = [24-y]/[6(y-6)]

  • 1 decade ago

    simply find the lcd, which in this case is 6(y-6)..

    multiply both numerators, and denominators, that are missing parts of the LCD,,

    and get (24-y)/6(y-6)

  • Philo
    Lv 7
    1 decade ago

    multiply 1st fraction by 6/6, 2nd by (y-6)/(y-6). You get

    18/(6y-36) + (6-y)/(6y-36) = (24-y) / (6y-36)

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