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Solve x2 + 7x + 6 = 0 for x?
Solve x2 + 7x + 6 = 0 for x
19 Answers
- SAMUEL DLv 71 decade agoFavorite Answer
x² + 7x + 6 = 0
(x + 6) (x + 1)
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Roots
x + 6 = 0
x + 6 - 6 = 0 - 6
x = - 6
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x + 1 = 0
x + 1 - 1 = 0 - 1
x = - 1
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x = - 6
or
x = - 1
- - - - - - - -s-
- PhiloLv 71 decade ago
x² + 7x + 6 = 0
x² + 7x = -6
x² + 7x + (7/2)² = -6 + (7/2)²
(x + 7/2)² = -24/4 + 49/4
(x + 7/2)² = 25/4
x + 7/2 = ± 5/2
x = -7/2 + 5/2 or x = -7/2 - 5/2
x = -2/2 or x = -12/2
x = -1 or x = -6
that's completing the square, which always works, but factoring, when it works, is easier.
x² + 7x + 6 = 0
(x + 6)(x + 1) = 0
x + 6 = 0 or x + 1 = 0
x = -6 or x = -1
- 1 decade ago
x^2 + 7x + 6 = 0
(x + 1)(x + 6) = 0
(x + 1) = 0 or (x + 6) = 0
x = -1 x = -6
- 1 decade ago
just sustitute
0 x 2 + 7 x 0 + 6 = 20
multiply 2 and 7 by 0 then add the products then add 6!
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- 1 decade ago
I assume X2 means X^2 and it is a quadratic equation.
factor or use the quadratic formula
I chose to factor as it factors easily w/o doing a lot of algebra
(X+1)(X+6)=0 therefore:
X= -1
and X= -6
- Sherman81Lv 61 decade ago
x^2 + 7x + 6 = 0
(x + 1)(x + 6) = 0
x = -1 or -6
If you aren't certain of an answer, you can always do this.
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-7 ± sqrt(7^2 - 4(1)(6)))/(2(1))
x = (-7 ± sqrt(49 - 24))/2
x = (-7 ± sqrt(25))/2
x = (-7 ± 5)/2
x = (-12/2) or (-2/2)
x = -6 or -1
- Anonymous1 decade ago
x ^2+7x+6
=x^2+x+6x+6
=x(x+1)+6(x+1)
=(x+1)(x+6)
i.e,x=-1 or x=-6
- ignoramusLv 71 decade ago
(x+1) (x+6) =0
divide first by x +6
x+1 = 0
x = -1
next divide top equation by x +1
then, x+6 =0
x= -6