# i need help with some pre calc. plz?

6. a triangle with an area of 16 has a base of (x+1) and a height of (x-13) fine the value of x along with the base and the height of the triangle.

1. between what two consecutive intergers is the value of log 66

2

7. express (6-3i)^2 in a+bi form.

2. which equation represents a circle with a center of (2,-3) and a radius of 6

### 5 Answers

- Jim BurnellLv 61 decade agoFavorite Answer
6.

A = 1/2bh

16 = 1/2(x + 1)(x - 13) = 1/2(x² -12x -13) = 1/2x² - 6x - 13/2

32 = x² - 12x - 13

0 = x² - 12x - 45

0 = (x - 15)(x + 3)

Throw out -3, so x = 15, the base is 16 and the height is 2.

2)

log 66 is between 1 and 2, because it's bigger than 10 (log 10 = 1) and less than 100 (log 100 = 2).

3)

(6 - 3i)² = 36 - 36i + 9i² = 36 - 36i - 9 = 27 - 36i

4)

(x - h)² + (y - k)² = r²

(x - 2)² + (y + 3)² = 6²

or in "standard form":

x² - 2x + 4 + y² + 6x + 9 = 36

x² - 2x + y² + 6x - 23 = 0

- Login to reply the answers

- yupchageeLv 71 decade ago
6. a triangle with an area of 16 has a base of (x+1) and a height of (x-13) fine the value of x along with the base and the height of the triangle

A=16=.5bh=.5(x+1)(x-13)

32=x^2-12x-13

x^2-12x-45=0

(x-15)(x+3)

only x-15=0

x=15 has physical meaning

so x=15

b=x+1=16

h=x-13=2

1. between what two consecutive intergers is the value of log 66

log 10=1

log 100=2

66 is between 10 & 100, so log 66 is between 1 & 2.

7. express (6-3i)^2 in a+bi form.

36-2*3*6i+9i^2

36-9-36i

25-36i

2. which equation represents a circle with a center of (2,-3) and a radius of 6

(x-2)^2+(y+3)^2=36

- Login to reply the answers

- 1 decade ago
6. you just need to set up an equation and solve for x. area of a triangle = 1/2 base * height so...

16 = ((x+1)/2) * (x-13)

simplify this function by multiplying each side by 2.

32 = (x + 1) * 2(x-13)

you should be able to solve from here

- Login to reply the answers

- aeiouLv 71 decade ago
Area Triangle = a base x height

Area triangle = (x + 1)(x -13)

X' = -1

x" = 13

<>

- Login to reply the answers

- How do you think about the answers? You can sign in to vote the answer.
- Sherman81Lv 61 decade ago
6.)

A = (1/2)bh

16 = (1/2)(x + 1)(x - 13)

32 = x^2 - 13x + x - 13

x^2 - 12x - 45 = 0

(x - 15)(x + 3) = 0

x = 15 or -3

Since you can't have a negative length

ANS : 16in base and 2 in height.

----------------------------------------------------------

1.) log(66) = 1.82

ANS : 1 and 2

-------------------------------------

7.)

(6 - 3i)^2

(6 - 3i)(6 - 3i)

36 - 18i - 18i + 9i^2

36 - 36i + 9(-1)

36 - 36i - 9

27 - 36i

-----------------------------------

2.)

(x - 2)^2 + (y - (-3))^2 = 6^2

(x - 2)^2 + (y + 3)^2 = 36

- Login to reply the answers