Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 decade ago

physics problem?

IN electic generator is connected to a factory by 2 wires of length 1 km each. The p.d. at generator is 230v and at the factory is 220v.THEcurrent intenisty in the wires is 50A. IF the resestivity of the material of the wire is (1.57 * 10 ^ -6)ohmcm.FIND the resistanceer meter of the wire and its radius.

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  • Som™
    Lv 6
    1 decade ago
    Favorite Answer

    Potential drop = 230-220 = 10 V

    By Ohms Law,

    Current(I)*R= V

    R=10/50 = 0.2 ohms

    Resistance is 0.2 ohms

    R=P*l/A

    p=(1.57 * 10 ^ -6)ohmcm

    l = 2km = 2*100000 cm= 200000cm

    A= P*l/R = 1.57*10^-6*2*10^5/0.2 = 1.57 cm^2

    A= pi*r^2 = 1.57 (since wire is cylindrical CS area is circular)

    r = 0.707 cm

    Radius of wire= 0.707 cm

    Source(s): myself
  • 1 decade ago

    what problem with your head

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