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Math problem >_<?

Models company revenue is R=-15p^2+300p+12000, where p is the price in dollars of the company's product.

1. What price will maximize revenue?

2.What is the maximum revenue?

2 Answers

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  • 1 decade ago
    Favorite Answer

    to answer this type of problem just use a graphing calculator, type the problem into Y1, graph, zoom out until you can see the curvature of the graph and then use the maximun feature, found by hitting the 2nd calc function

    answers

    1. 10

    2. 13,500

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  • Mitch
    Lv 7
    1 decade ago

    It's pretty simple, just use the vertex formula:

    - b

    ----

    2 a

    Where:

    a = -15

    b = 300

    - 300

    ---------

    2 (-15)

    - 300

    ---------

    - 30

    Max price = 10 dollars.

    ..................

    Now, plug the max price into the equation:

    R = -15 (10)^2 + 300 (10) + 12000

    R = -15 (100) + 3000 + 12000

    R = -1500 + 3000 + 12000

    R = $13,500

    Good luck in your classes.

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