# Math problem >_<?

Models company revenue is R=-15p^2+300p+12000, where p is the price in dollars of the company's product.

1. What price will maximize revenue?

2.What is the maximum revenue?

### 2 Answers

Relevance

- 1 decade agoFavorite Answer
to answer this type of problem just use a graphing calculator, type the problem into Y1, graph, zoom out until you can see the curvature of the graph and then use the maximun feature, found by hitting the 2nd calc function

answers

1. 10

2. 13,500

- Login to reply the answers

- MitchLv 71 decade ago
It's pretty simple, just use the vertex formula:

- b

----

2 a

Where:

a = -15

b = 300

- 300

---------

2 (-15)

- 300

---------

- 30

Max price = 10 dollars.

..................

Now, plug the max price into the equation:

R = -15 (10)^2 + 300 (10) + 12000

R = -15 (100) + 3000 + 12000

R = -1500 + 3000 + 12000

R = $13,500

Good luck in your classes.

- Login to reply the answers

Still have questions? Get your answers by asking now.