How do I Divide:?

x2 – 3x + 2 ÷ x2 – 4

_________ ______

8x – 8 5x + 10

4 Answers

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  • 1 decade ago
    Favorite Answer

    [(x^2 - 3x + 2)/(8x - 8)] / [(x^2 - 4)/5x + 10)]

    First: factor each numerator and denominator:

    = [(x - 2)(x - 1)/8(x - 1)] / [(x + 2)(x - 2)/5(x + 2)]

    Second: cancel "like" terms from each fraction > cancel (x - 1) and (x + 2):

    = [(x - 2)/8] / [(x - 2/5)]

    Third: the rule is "you can't divide fractions" - change the division sign into multiplication and flip the second fraction:

    = [(x - 2)/8] [5/(x - 2)]

    = 5/8

  • Anonymous
    1 decade ago

    Multiply by the reciprocal... aka, keep switch flip.

    what i mean...

    Factor everything and

    Keep the first fraction perfect- leave it alone

    Swith the divide sign to a multiply sign

    Flip the second so that x2-4 is on the bottom

    so now, factored and switched it looks like

    (x-2) (x-2)

    ------- * -------------

    8 5

    then just multiply so its

    (x-2)(x-2)

    --------------

    40

    or (x-2)2

    ---------- <-------the outside "2" is to say "squared"

    40

  • 1 decade ago

    (x-1)(x-2)/8(x-1)*5(x+2)/(x+2)(x-2)=(x-2)/8*5/(x-2)=5(X-2)/8(X-2)=5/8 for x different by 1,2,-2.END!!

  • Anonymous
    1 decade ago

    all the answers are correct

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