### 4 Answers

- ♪♥Annie♥♪Lv 61 decade agoFavorite Answer
[(x^2 - 3x + 2)/(8x - 8)] / [(x^2 - 4)/5x + 10)]

First: factor each numerator and denominator:

= [(x - 2)(x - 1)/8(x - 1)] / [(x + 2)(x - 2)/5(x + 2)]

Second: cancel "like" terms from each fraction > cancel (x - 1) and (x + 2):

= [(x - 2)/8] / [(x - 2/5)]

Third: the rule is "you can't divide fractions" - change the division sign into multiplication and flip the second fraction:

= [(x - 2)/8] [5/(x - 2)]

= 5/8

- Anonymous1 decade ago
Multiply by the reciprocal... aka, keep switch flip.

what i mean...

Factor everything and

Keep the first fraction perfect- leave it alone

Swith the divide sign to a multiply sign

Flip the second so that x2-4 is on the bottom

so now, factored and switched it looks like

(x-2) (x-2)

------- * -------------

8 5

then just multiply so its

(x-2)(x-2)

--------------

40

or (x-2)2

---------- <-------the outside "2" is to say "squared"

40

- 1 decade ago
(x-1)(x-2)/8(x-1)*5(x+2)/(x+2)(x-2)=(x-2)/8*5/(x-2)=5(X-2)/8(X-2)=5/8 for x different by 1,2,-2.END!!

- Anonymous1 decade ago
all the answers are correct