Anonymous asked in Science & MathematicsMathematics · 1 decade ago


eliminate @:

1. x=b tan@, y=a sec@

2. x=tan@ y=a sin@

3. x=sin@+ cos@, y=sin@-cos@


3 Answers

  • 1 decade ago
    Favorite Answer

    1. Using the identity: (tan x)^2 + 1 = (sec x)^2

    x^2=b^2 (tan@)^2 and y^2=a^2 (sec@)^2

    then rearrange to get: (tan@)^2 as the subject and (sec@)^2 as the subject. By taking one away from the other, this implies:

    x^2/b^2-y^2/a^2= -1

  • 1 decade ago


    y^2/a^2 - x^2/b^2=1

    it is an hyperbola

    2.(got a little trouble with this)

    a^2*x^2 - x^2*y^2 - y^2 = 0

    some sort of weird curve

    3.(this was my favorite)

    x^2 + y^2 = 2

    it's a circle

    i have the procedures in paper if u want them..

    Source(s): school ;D
  • 1 decade ago

    I think it's trigonometry


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