Anonymous

# trignomotry?

eliminate @:

1. x=b tan@, y=a sec@

2. x=tan@ y=a sin@

3. x=sin@+ cos@, y=sin@-cos@

cheers

### 3 Answers

Relevance

- 1 decade agoFavorite Answer
1. Using the identity: (tan x)^2 + 1 = (sec x)^2

x^2=b^2 (tan@)^2 and y^2=a^2 (sec@)^2

then rearrange to get: (tan@)^2 as the subject and (sec@)^2 as the subject. By taking one away from the other, this implies:

x^2/b^2-y^2/a^2= -1

- 1 decade ago
1.

y^2/a^2 - x^2/b^2=1

it is an hyperbola

2.(got a little trouble with this)

a^2*x^2 - x^2*y^2 - y^2 = 0

some sort of weird curve

3.(this was my favorite)

x^2 + y^2 = 2

it's a circle

i have the procedures in paper if u want them..

Source(s): school ;D

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