# Graph the inequality!!!!?

How am I suppose to graph 2x - y + 3 greater than or equal to 0? Do I need to solve for x and y? If so how in the hell do I do it? Please help! I really don't understand. Show your work and please also explain along the way.

Thanks!

Relevance

Solve for y,

2x - y + 3 >= 0

2x + 3 >= y

y <= 2x + 3

Now draw the line y = 2x + 3 and shade everything below it.

The line is in slope-intercept form. Two points are (0, 3) and (-3/2, 0). Draw the line that passes through both of them.

As a convention let's represent "greater than or equal to" with ">=", okay?

You can put 2x - y + 3 >= 0 in slope-intercept form:

2x + 3 >= y,

Rewrite the inequality so that 'y' is on the left side:

y <= 2x + 3 (note the change in the inequality symbol),

You can draw the line y = 2x + 3; the slope is 2 and the line passes through (0, 3).

Because we have that y is also less than all this, you can shade the entire region lying below the line.

If the question was originally phrased with "greater than" instead of "greater than or equal to," you would draw a dotted line instead of a solid line (and still shade the underlying region).