Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

How do i graph a y^2 parabola and find the focus?

I need to find the focus!!!

Update:

equation is (y+4)^2= -16(x-3)

1 Answer

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  • raj
    Lv 7
    1 decade ago
    Favorite Answer

    is it y^2=x

    then the ordered pairswill be

    (-3,9),(-2,4),(-1,1),(0,0),(1,1),(2,4,(3,9)

    plot the graph now

    vertex(0,0)

    focus(1/4,0)

    Additional Details

    31 seconds ago

    equation is (y+4)^2= -16(x-3)

    (y+4)^2=-4*4(x-3)

    shifting theoriginto (3,-4) this reduces to

    Y^2=-4aX =>4a=16 so a=4

    referred to X,Y axes referred to x,y axes

    vertex:(0,0) (3,-4)

    Focus:(-4,0) (-1,-4)

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