## Trending News

Promoted

Anonymous

# How do i graph a y^2 parabola and find the focus?

I need to find the focus!!!

Update:

equation is (y+4)^2= -16(x-3)

### 1 Answer

Relevance

- rajLv 71 decade agoFavorite Answer
is it y^2=x

then the ordered pairswill be

(-3,9),(-2,4),(-1,1),(0,0),(1,1),(2,4,(3,9)

plot the graph now

vertex(0,0)

focus(1/4,0)

Additional Details

31 seconds ago

equation is (y+4)^2= -16(x-3)

(y+4)^2=-4*4(x-3)

shifting theoriginto (3,-4) this reduces to

Y^2=-4aX =>4a=16 so a=4

referred to X,Y axes referred to x,y axes

vertex:(0,0) (3,-4)

Focus:(-4,0) (-1,-4)

Still have questions? Get your answers by asking now.