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[(x-7)+y] [(x-7)-y]
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- PuzzlingLv 71 decade agoFavorite Answer
First multiply through using FOIL:
First: (x - 7)(x - 7)
Outer: -y(x - 7)
Inner: y(x - 7)
Last: - y²
The outer and inner terms cancel and you get:
(x - 7)² - y²
If you recognize that you have a = x - 7, and b = y, then you might have (a + b)(a - b) which results in a difference of squares (a² - b²). Either way, you get to the same result.
(x - 7)² - y²
Finally, expand (x - 7)²
(x² - 14x + 49) - y²
- Anonymous1 decade ago
[(x-7)+y] [(x-7)-y]
(x-7)^2 - y^2
x^2 - 14x +49 - y^2
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