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# How do you simplify these?

1. -20y^5 / 40y^2

2. 1 / m^0 + n^0

### 4 Answers

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- 1 decade agoFavorite Answer
1. (-20/40)(y^(5-3) = (-1/2) y^3

2. since m^0 = 1 and n^0 = 1, then 1/1 + 1 = 2

- 1 decade ago
1. aCancel the -20 with the 40 to create a 2 on the bottom

-y^5/2y^2

b. Subtract the powers of the y's

-y^(5-2) = -(y^3)/2

2. Anything to the power of 0 is 1 so

1/ m^0 = 1/1= 1

n^0 = 1

So the answer is 1 + 1 = 2

- SAMUEL DLv 71 decade ago
problem 1

- 20y^5 / 40y² =

- 1/2y³

The answer is - 1/2y³

- - - - - - - - - - - - -

Problem 2

1 / m^0 + n^0'

1 / 1 + 1 =

1 / 2

The answer is 1/2

- - - - - - -s-

- Anonymous1 decade ago
1.) -1y^3 / 2

2.) 1/2

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