# The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find

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The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

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L=18

W=8

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• Anonymous

Perimeter of the rectangle = 2( Length + Width)

Length = 2.width + 2 ...(1)

Length + Width = 52/2 ...(2)

Substituting (1) in (2),

3.Width + 2 = 26

Width = 8cm

Length = 18cm

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• Amanda - they're providing you with the training you want to remedy this one. one situation you realize to commence with is that the "perimeter" of the rectangle typically is the sum of the size of all 4 aspects, precise? So if the size of the rectangle is "l," and the width is "w," then the fringe will equivalent the size of the suitable and the bottom aspects, plus the suitable of the left and precise aspects. the fringe - enable's call it P, will = l + l + w + w, or P = 2 l + 2 w. Now, they have advised you a thanks to imagine about length, or "l," in words of width, or "w." in truth, l = w + 2 cm. Now, are you able to change (w + 2 cm) for l, interior the equation you've for P? in case you try this, you receives an equation for P that incorporates in common words "w" words and centimeters. and also you note of that P = fifty 2 centimeters. so so you could be in a position to discover the cost of w particularly certainly. you do not ignore that l = w +2, so once you realize what w is, you may then get what l is. and then you've solved the problem.

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• 52 = 2w + 2(2w + 2)

= 2w + 4w + 4

= 6w + 4

48 = 6w

8 = w

The width is 8, the length is 18.

2*8 + 2*18 = 16 + 36 = 52

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• Anonymous

P = 2(L + W)

L = (W + 2)

52 = 2((W + 2) + W)

52 = 2(2W + 2)

52 = 4W + 4

13 = W + 1

W = 12

L = 14

ANSWER: The width is 12 cm and the length is 14 cm.

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• L=(2W+2)

Perimeter=2W+2L

Perimeter=2W+2(2W+2)

52=2W+4W+4

48=6W

W=8

L=(2*8+2)=18

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• let x be the length of the rectangle and y be its width.

it is given that,

length of the rectangle=2cm + 2(width of the rectangle)

this implies that,

x=2+2y

OR x-2y=2 ........................(1)

also it is given that,

perimeter=52cm

this implies that,

2(x+y)=52

OR 2x+2y=52...................(2)

(2)+(1) gives,

3x=54

OR x=18

substituting x in (1),

18-2y=2

OR -2y = -16

OR y = -16/-2

OR y = 8

Hence,dimensions of the rectangle are

length = 18cm & breadth = 8cm

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• Anonymous

Set up a system of eqns:

L = 2+2w

P = 2w + 2L = 6w + 4 = 52

Solve for L and w, it should be an 18x8 rect.

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• width is 12 and length is 14

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• if its 2cm more u do...

let width b X

n length b X+2..

2X+2X+4=52

4X=48..

x=12

width =12cm

length=14cm

if its twice..

let width=x

length=2x

6x=52

x=8.6

width=8.67

lehgth=17.34

if its 2more than twice its width

then width=x

length=2X+2

4X+4+2X=52

6X=48

X=8

wdth=8

length=18

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