The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find

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The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

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  • 1 decade ago
    Favorite Answer

    L=18

    W=8

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  • Anonymous
    1 decade ago

    Perimeter of the rectangle = 2( Length + Width)

    Length = 2.width + 2 ...(1)

    Length + Width = 52/2 ...(2)

    Substituting (1) in (2),

    3.Width + 2 = 26

    Width = 8cm

    Length = 18cm

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  • 4 years ago

    Amanda - they're providing you with the training you want to remedy this one. one situation you realize to commence with is that the "perimeter" of the rectangle typically is the sum of the size of all 4 aspects, precise? So if the size of the rectangle is "l," and the width is "w," then the fringe will equivalent the size of the suitable and the bottom aspects, plus the suitable of the left and precise aspects. the fringe - enable's call it P, will = l + l + w + w, or P = 2 l + 2 w. Now, they have advised you a thanks to imagine about length, or "l," in words of width, or "w." in truth, l = w + 2 cm. Now, are you able to change (w + 2 cm) for l, interior the equation you've for P? in case you try this, you receives an equation for P that incorporates in common words "w" words and centimeters. and also you note of that P = fifty 2 centimeters. so so you could be in a position to discover the cost of w particularly certainly. you do not ignore that l = w +2, so once you realize what w is, you may then get what l is. and then you've solved the problem.

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  • 1 decade ago

    52 = 2w + 2(2w + 2)

    = 2w + 4w + 4

    = 6w + 4

    48 = 6w

    8 = w

    The width is 8, the length is 18.

    Check your answer. 18 is twice 8 + 2.

    2*8 + 2*18 = 16 + 36 = 52

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  • Anonymous
    1 decade ago

    P = 2(L + W)

    L = (W + 2)

    52 = 2((W + 2) + W)

    52 = 2(2W + 2)

    52 = 4W + 4

    13 = W + 1

    W = 12

    L = 14

    ANSWER: The width is 12 cm and the length is 14 cm.

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  • 1 decade ago

    L=(2W+2)

    Perimeter=2W+2L

    Perimeter=2W+2(2W+2)

    52=2W+4W+4

    48=6W

    W=8

    L=(2*8+2)=18

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  • 1 decade ago

    let x be the length of the rectangle and y be its width.

    it is given that,

    length of the rectangle=2cm + 2(width of the rectangle)

    this implies that,

    x=2+2y

    OR x-2y=2 ........................(1)

    also it is given that,

    perimeter=52cm

    this implies that,

    2(x+y)=52

    OR 2x+2y=52...................(2)

    (2)+(1) gives,

    3x=54

    OR x=18

    substituting x in (1),

    18-2y=2

    OR -2y = -16

    OR y = -16/-2

    OR y = 8

    Hence,dimensions of the rectangle are

    length = 18cm & breadth = 8cm

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  • Anonymous
    1 decade ago

    Set up a system of eqns:

    L = 2+2w

    P = 2w + 2L = 6w + 4 = 52

    Solve for L and w, it should be an 18x8 rect.

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  • 1 decade ago

    width is 12 and length is 14

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  • 1 decade ago

    if its 2cm more u do...

    let width b X

    n length b X+2..

    2X+2X+4=52

    4X=48..

    x=12

    width =12cm

    length=14cm

    if its twice..

    let width=x

    length=2x

    6x=52

    x=8.6

    width=8.67

    lehgth=17.34

    if its 2more than twice its width

    then width=x

    length=2X+2

    4X+4+2X=52

    6X=48

    X=8

    wdth=8

    length=18

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