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# The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find

The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

### 14 Answers

- Anonymous1 decade ago
Perimeter of the rectangle = 2( Length + Width)

Length = 2.width + 2 ...(1)

Length + Width = 52/2 ...(2)

Substituting (1) in (2),

3.Width + 2 = 26

Width = 8cm

Length = 18cm

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- melgozaLv 44 years ago
Amanda - they're providing you with the training you want to remedy this one. one situation you realize to commence with is that the "perimeter" of the rectangle typically is the sum of the size of all 4 aspects, precise? So if the size of the rectangle is "l," and the width is "w," then the fringe will equivalent the size of the suitable and the bottom aspects, plus the suitable of the left and precise aspects. the fringe - enable's call it P, will = l + l + w + w, or P = 2 l + 2 w. Now, they have advised you a thanks to imagine about length, or "l," in words of width, or "w." in truth, l = w + 2 cm. Now, are you able to change (w + 2 cm) for l, interior the equation you've for P? in case you try this, you receives an equation for P that incorporates in common words "w" words and centimeters. and also you note of that P = fifty 2 centimeters. so so you could be in a position to discover the cost of w particularly certainly. you do not ignore that l = w +2, so once you realize what w is, you may then get what l is. and then you've solved the problem.

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- 1 decade ago
52 = 2w + 2(2w + 2)

= 2w + 4w + 4

= 6w + 4

48 = 6w

8 = w

The width is 8, the length is 18.

Check your answer. 18 is twice 8 + 2.

2*8 + 2*18 = 16 + 36 = 52

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- Anonymous1 decade ago
P = 2(L + W)

L = (W + 2)

52 = 2((W + 2) + W)

52 = 2(2W + 2)

52 = 4W + 4

13 = W + 1

W = 12

L = 14

ANSWER: The width is 12 cm and the length is 14 cm.

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- 1 decade ago
L=(2W+2)

Perimeter=2W+2L

Perimeter=2W+2(2W+2)

52=2W+4W+4

48=6W

W=8

L=(2*8+2)=18

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- 1 decade ago
let x be the length of the rectangle and y be its width.

it is given that,

length of the rectangle=2cm + 2(width of the rectangle)

this implies that,

x=2+2y

OR x-2y=2 ........................(1)

also it is given that,

perimeter=52cm

this implies that,

2(x+y)=52

OR 2x+2y=52...................(2)

(2)+(1) gives,

3x=54

OR x=18

substituting x in (1),

18-2y=2

OR -2y = -16

OR y = -16/-2

OR y = 8

Hence,dimensions of the rectangle are

length = 18cm & breadth = 8cm

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- Anonymous1 decade ago
Set up a system of eqns:

L = 2+2w

P = 2w + 2L = 6w + 4 = 52

Solve for L and w, it should be an 18x8 rect.

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- 1 decade ago
if its 2cm more u do...

let width b X

n length b X+2..

2X+2X+4=52

4X=48..

x=12

width =12cm

length=14cm

if its twice..

let width=x

length=2x

6x=52

x=8.6

width=8.67

lehgth=17.34

if its 2more than twice its width

then width=x

length=2X+2

4X+4+2X=52

6X=48

X=8

wdth=8

length=18

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