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can anyone solve this geometry??
imagine there's a trapezium ABDC......
AB = BD
CD = 21 cm
B = 120 degrees
BD = ?
- 1 decade agoFavorite Answer
first, i want to ask you, where do you live?
Are you in US or in England?
Coz these two countries have different definition of trapezoid and trapezium.
According to US
trapezoid is a quadrilateral with one pair of parallel sides.
trapezium is a quadrilateral with no pair of parallel sides.
While in England
trapezoid is a quadrilateral with no pair of parallel sides.
trapezium is a quadrilateral with one pair of parallel sides.
which one is your question.
If your thinking of a quadrilateral with no pair of parallel sides,
there is no asnwer to your question.
actually, there is, but the solutions is actually a family of curves.
If your thinking of a quadrilateral with one pair of parallel sides,
here's the solution:
i assume that sides AB and CD are parallel sides since you did not specify which one is the paralle sides.
By inspection, the trapezoid is actually an equilateral trapezoid.
if this is the case, we can conclude that
AB = BC = AD
Now taking the right triangle on its side, we get
hypotenuse = x
base = (21-x)/2
actually, the triangle is a 30-60-90 triangle.
according to this, the base is half of the hypotenuse.
[(21-x)/2]/2 = x
solving for x, we get
x = 21/5
AC = BD
by using cosine law
AC^2 = x^2 + x^2 - 2x^2 cos 120
AC^2 = x^2 + x^2 + x^2
AC^2 = 3x^2
AC = x sqrt(3)
since x = 21/5
AC = (21/5) * sqrt(3)
BD = (21/5) * sqrt(3)
BD = 7.274613392
sorry, it took time to finish my novel.
- 1 decade ago
Imagine the trapezioid ABCD.
By geometric inspection, similar angles, and sine rule(see below)
sin60/DB = sin45/21 >>>hence DB=18.82
If I drew it as in your book, it should be right.Source(s): my brain!
- jamoncitaLv 51 decade ago
i know! i know! YOU CAN!! good luck! :D