SonRK asked in Science & MathematicsPhysics · 1 decade ago

Potential Energy and Conservation of Energy Question 2.?

A 2.0kg block is dropped from a height of 40 cm onto a spring of spring constant k = 1960 N/m. Find the maximum distance the spring is compressed.

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  • 1 decade ago
    Favorite Answer

    F = ma = 2 * 9.8 = 19.6

    F(spring) = k*(distance compressed)

    19.6 = 1960 * x

    X = 19.6 / 1960

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  • Steve
    Lv 7
    1 decade ago

    The PE lost by the block when it stops is mg(.40 + Δ)

    The spring when fully deflected will store this energy AND support the weight of the block. So,

    .5kΔ² = mg(.4 + Δ) → Δ = .03254 m

    y(due to weight) = W/k = mg/k = .01 m

    Total deflection = y + Δ = .04254 m

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