# I have to solve this equation by finding what H is. Can you show me the steps?

.96-19.44H^ -2 = 0

Relevance

Subtract 0.96 from both sides:

-19.44H^-2 = -0.96

Multiply both sides by H²:

-19.44 = -0.96*H²

Divide both sides by -0.96

H² = 19.44 / 0.96

Simplify and reduce:

H² = 1944 / 96

H² = 81 / 4

Take the square root of both sides

H = sqrt(81 / 4)

H = ±(9/2)

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• H^-2 is equivalent to 1/(H^2)

1.original equasion

.96-19.44H^-2 = 0

2.subtract .96 from each side

-19.44H^-2 = -.96

3. multiply both sides by (-1)

19.44H^-2 = .96

4. divide both sides by 19.44. since 19.44/19.44=1, we can simply write:

H^-2 = .96/19.44

5. to simplify .96/19.44, we can multiply top and bottom by 100, getting 96/1944 = 4/81

6. therefore

H^-2 = 4/81

7. inverting both sides

H^2 = 81/4

8. take square root of both sides

H = sqrt(81/4)

9. using example 6 in http://www.themathpage.com/alg/simplify-radicals-2...

H = sqrt(81 * 1/4)

H = 1/2 sqrt (81)

10 sqrt(81) = 9, so

H = 1/2 * 9 = 4.5

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• Subtract .96 from each side

-19.44H^-2 = -.96

Divide by -19.44

H^-2 = -.96/-19.44

H^2 = 19.44/.96

H^2 = 20.25

H=4.5

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• Anonymous

0 = 0.96 - 19.44H^2

Subtract 0.96 from both sides

-0.96 = 19.44H^2

Divide bith sides by 19.44

(-0.96 / 19.44) = H^2

Take the square root of both sides

H = (-0.96 / 19.44) ^0.5

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