I have to solve this equation by finding what H is. Can you show me the steps?

.96-19.44H^ -2 = 0

4 Answers

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  • 1 decade ago
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    Subtract 0.96 from both sides:

    -19.44H^-2 = -0.96

    Multiply both sides by H²:

    -19.44 = -0.96*H²

    Divide both sides by -0.96

    H² = 19.44 / 0.96

    Simplify and reduce:

    H² = 1944 / 96

    H² = 81 / 4

    Take the square root of both sides

    H = sqrt(81 / 4)

    H = ±(9/2)

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  • 1 decade ago

    according to http://www.themathpage.com/alg/negative-exponents....

    H^-2 is equivalent to 1/(H^2)

    1.original equasion

    .96-19.44H^-2 = 0

    2.subtract .96 from each side

    -19.44H^-2 = -.96

    3. multiply both sides by (-1)

    19.44H^-2 = .96

    4. divide both sides by 19.44. since 19.44/19.44=1, we can simply write:

    H^-2 = .96/19.44

    5. to simplify .96/19.44, we can multiply top and bottom by 100, getting 96/1944 = 4/81

    6. therefore

    H^-2 = 4/81

    7. inverting both sides

    H^2 = 81/4

    8. take square root of both sides

    H = sqrt(81/4)

    9. using example 6 in http://www.themathpage.com/alg/simplify-radicals-2...

    H = sqrt(81 * 1/4)

    H = 1/2 sqrt (81)

    10 sqrt(81) = 9, so

    H = 1/2 * 9 = 4.5

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  • 1 decade ago

    Subtract .96 from each side

    -19.44H^-2 = -.96

    Divide by -19.44

    H^-2 = -.96/-19.44

    H^2 = 19.44/.96

    H^2 = 20.25

    H=4.5

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  • Anonymous
    1 decade ago

    0 = 0.96 - 19.44H^2

    Subtract 0.96 from both sides

    -0.96 = 19.44H^2

    Divide bith sides by 19.44

    (-0.96 / 19.44) = H^2

    Take the square root of both sides

    H = (-0.96 / 19.44) ^0.5

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