What is and how do you find the derivative of The sq root of [(2x^3 -7) / (4x +1)]?
The whole equation is under the square root.
- Anonymous1 decade agoFavorite Answer
You'd have to use the chain rule for the square root, then the quotient rule for what's inside.
f ' (x) = (1/2) [(2x³ - 7) / (4x + 1)]^(-1/2) times the derivative of the radicand.
For that, the quotient rule gives:
[6x²(4x + 1) - 4(2x³ - 7)] / (4x + 1)²
There's most likely some simplifying to be done, but that should get you on the right path.
- 1 decade ago
That's about as simplified as it get. Is it in an algebric equation? Then you could solve for X if that was the case.