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# What is and how do you find the derivative of The sq root of [(2x^3 -7) / (4x +1)]?

The whole equation is under the square root.

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- Anonymous1 decade agoFavorite Answer
You'd have to use the chain rule for the square root, then the quotient rule for what's inside.

f ' (x) = (1/2) [(2x³ - 7) / (4x + 1)]^(-1/2) times the derivative of the radicand.

For that, the quotient rule gives:

[6x²(4x + 1) - 4(2x³ - 7)] / (4x + 1)²

There's most likely some simplifying to be done, but that should get you on the right path.

Good luck!

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- 1 decade ago
That's about as simplified as it get. Is it in an algebric equation? Then you could solve for X if that was the case.

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