y=x^3 + 2x using dy/dx?
Using the formula y=x^3 + 2x, I am to using deriatives, find the equation of the tangent line. Any help would be appreciated!
- ludacrusherLv 41 decade agoFavorite Answer
equation of the tangent of the line is the derivative of the line
dy/dx = 3x^2 + 2
- stephen mLv 41 decade ago
dy/dx = 3x^2 + 2.
The equation of a line is (y-y1) = m(x-x1)
So, the find the tangent line going through x1=a:
y1 = a^3 + 2a
m = 3a^2 + 2
So y - (a^3 + 2a) = (3a^2 + 2)(x-a).
You could expand and rearrange if you want.
- 1 decade ago
(dy/dx) = (3 x^2 )+ 2