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# solve the following equation?

3^4= -2x^2+8

### 3 Answers

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- 1 decade agoFavorite Answer
3^4 = -2x^2 + 8

81 = -2x^2 + 8 simplify

73 = -2x^2 subtract 8 from both sides

-73/2 = x^2 divide both sides by -2

sqrt(73/2) * i = x take square root of both sides... since the right is negative you get an imaginary number. i = sqrt(-1)

- Anonymous1 decade ago
3^4= 81

81=-2x^2+8

73=-2x^2

-73/2=x^2

no answer. cannot take the square root of a negative, unless i did something wrong. unless you use imaginary numbers then its...

iV73/2

- 1 decade ago
are you in highschool or smth?

x^2=-(81-8)/2=-73/2

x=i*(73/2)^(1/2)

or

x=-i*(73/2)^(1/2)

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