solve the following equation?

3^4= -2x^2+8

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  • 1 decade ago
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    3^4 = -2x^2 + 8

    81 = -2x^2 + 8 simplify

    73 = -2x^2 subtract 8 from both sides

    -73/2 = x^2 divide both sides by -2

    sqrt(73/2) * i = x take square root of both sides... since the right is negative you get an imaginary number. i = sqrt(-1)

  • Anonymous
    1 decade ago

    3^4= 81

    81=-2x^2+8

    73=-2x^2

    -73/2=x^2

    no answer. cannot take the square root of a negative, unless i did something wrong. unless you use imaginary numbers then its...

    iV73/2

  • 1 decade ago

    are you in highschool or smth?

    x^2=-(81-8)/2=-73/2

    x=i*(73/2)^(1/2)

    or

    x=-i*(73/2)^(1/2)

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