# Can anyone help me with a complicated math problem?

The math problem is 7 6 = 4 2. You can't add any symbols to it. You can use powers because that isn't using symbols. I can't seem to figure out how to make it work out. Please help!!!!

Update:

You can rearrange the numbers, but you can't add any symbols to the equation. There's supposedly an actual answer, but nobody here can seem to figure it out. You can use exponents, but you can't add ANYTHING to the equation, including other numbers.

Relevance

Ok, take it back.

Flip the 6, turn it into a 9. Move it over to the right hand side, move the 2 to an exponent over the 7.

7^2 = 49.

That's it.

Rearrange the numbers. Take the 7 and raise it to the second power (7^2), and on the other side of the equal side, turn the 6 upside down to make a 9, and put it next to the 4. 7^2 = 49

• Roslyn
Lv 4
4 years ago

well, it takes her 30 min, because the hands were together then exactly opposite, in order to do this, half an hour must have past. For the other part, if you think about the tic marks on a a clock, there are five marks between hours (after the four to the five.) So, each mark represents a 12 minute increment. Now, in order to for the hands to start out on top of eachother, she would have needed to start at least around 4: 20 (a little after actually). It can't be at the 36 minute tick mark, b/c then it's too late to complete the half hour, so the start is around 4:24 and the end 4:54 but you'll have to do the finer tuning yourself ^^

• fcas80
Lv 7

7 times 6 = 42

You don't need a symbol between the 4 and the 2.

You can leave the 7 6 as is, because the implied operation is multiplication.

7^0 6^0 = 4^0 2^0

The reason you have a space between the 7 and 6 and also between the 4 and 2 is unclear.

If multiplication is implied, then my solution gives 1*1=1*1.

If it means 76=42 , themy solution gives 11=11.

I have used only exponents as you directed.

More of a logic problem, not math, although you have to use math to know that anything other than x^2 would be too large to be a potential solution. Actually takes some lateral thinking to come up with flipping the 6.

Zen got it right.

7^0 6^0 = 4^0 2^0

where there is an implied multiplication.

Or

7^a 6^b = 4^c 2^(log((6^b 7^a)/4^c))

Or

76^0 = 42^0

Or

76^a = 42^(a ln76/ln42)

• cfpops
Lv 5

Don't quite understand the rules, but here is a shot:

7 times 6 = 4 tens and a 2