# math help mathematicians!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!?

1)The price of the tickets went up from \$48 to \$58: 56. What percent of a change does this represent?

(Hint: the change is what percent of the original price?)

2) We have 73 coins, all dimes and quarters, in the value of \$13. How many quarters, how many

dimes?

Relevance
• 1 decade ago

1) Percentage change = [(new price - old price) / old price] x 100

so:

[(\$58.56 - \$48) / \$48] x 100 = 22%

2)

a + b = 73

where a = number of dimes

where b = number of quarters

[ie. some number of dimes plus some number of quarters equals 73 coins]

First, write it in terms of dollar value.

(\$0.10 x a) + (\$0.25 x b) = \$13

[this means: some number of dimes multiplied by their dollar value, plus some number of quarters multiplied by their dollar value, equals \$13]

Remember that "a + b = 73"?

It can be written as "a = 73 - b"

Put this relationship into: (\$0.10 x a) + (\$0.25 x b) = \$13

(\$0.10 x [73 - b]) + (\$0.25 x b) = \$13

Which gives:

\$7.3 - 0.1b + 0.25b = \$13

Organise the "b"s into one side, the integers into the other:

0.15b = 5.7

b = 38

This means you need 38 quarters.

Since you had a total of 73 coins to play with, and 38 are already known to be quarters, 35 must be dimes.

• Anonymous

1) You want the percentage of the second value compared to the first value which is 58.56?48=1.22=122%

2) you want to right two equations representing how many dimes and quarters you have and there values.

25q+10d=1300

q+d=73

the second equation gives you q=73-d

input that value for q in the first equation you get

25(73-d)+10d=1300

1825-15d=1300

subtract 1825 from both sides

-15d=-525

divide by -15

d=35

then use our equation from earlier

to get 73-35=38=q

So we have 35 dimes and 38 quarters

• 1 decade ago

% Change = Change / Original Price x 100

% = (48 - 58)/48 x 100

you do the math.

D = Dime

Q = Quarter

0.10D + 0.25Q = 13

D + Q = 73

10D + 25Q = 1300

10D + 10Q = 730

Subtract the equations

15Q = 570

Q = 38

D = 35

• Anonymous

1) 48 + 48*p/100 = 58.56

48p/100 = 10.56

p=10.56*100/48 = 22%

2) x number of dimes and y number of quarters

x+y = 73 => x=73 - y

0.1 x + 0.25 y = 13 => 0.1(73 - y) + 0.25y = 13

7.3 - 0.1y + 0.25y = 13

0.15 y = 5.7

so y=38

and x=35

• 1 decade ago

2)

d + q = 73

10d + 25q = 1300

..................

d = 73 - q

10(73 - q) + 25q = 1300

730 - 10q + 25q = 1300

15q = 1300 - 730 = 570

q = 570/15 = 38

d = 73 - 38 = 35

.... check

10d + 25q = 1300

10(35) + 25(38) = 350 + 950 = 1300

(you made a typo in other problem and don't get it)

• 1 decade ago

1) 58.56 / 48 = 1.22. Therefore it increased by 22%.

2)

0.25x + 0.1 * (73 - x) = 13

0.15x + 7.3 = 13

0.15 * x = 5.7

x = 38 quarters

73 - x = 35 dimes

• 1 decade ago

1.) (48-58)/48

2.) use 2 equations,

where x=dimes

y=quarters

1st equation x+y=73

2nd equation 0.1*x+0.25*y=13

you do the computations, i dont have a calculator n_n