Herrick asked in 科學及數學數學 · 1 decade ago

how to contruct sqrt 5,10, 29, 7 on the no. line

how to contruct sqrt 5,10, 29, 7 on the no. line

1 Answer

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  • 1 decade ago
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    Construct a suitable right angled triangle on the number line. Note that

    √5 = √(2^2 + 1^2)..........[Draw a right angled triangle with base = 2, height = 1]

    √10 = √(3^2 + 1^2)........[Draw a right angled triangle with base = 3, height = 1]

    √29 = √(5^2 + 2^2)........[Draw a right angled triangle with base = 5, height = 2]

    For √7, it is more complicated:

    √2 = √(1^2 + 1^2).......[Draw a right angled triangle with base = 5, height = 2]

    √3 = √[(√2)^2 + 1^2]

    ..............[Draw a right angled triangle with base = √2, height = 1]

    √7 = √((√3)^2 + 2^2)

    ..............[Draw a right angled triangle with base = √3, height = 2]

    Hope that you know what I mean......

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