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# What percent of time was spent in the air? see details?

In 1995, an aircraft set the around the-world record time for a passenger jet at 31h,27min,49s. Six refueling stops took a total of 8h, 48min,8s.

### 5 Answers

- James LLv 51 decade agoFavorite Answer
The total number of seconds the trip took is

31*3600+27*60+49 = 113269

The total number of seconds spent refueling is

8*3600+48*60+8 = 31688

Therefore, the percentage of time spent in the air is

100*(113269-31688)/113269 = 72.0241%.

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- China JonLv 61 decade ago
First turn everything in to seconds, and divide.

31h 27min 49s = 113,269 seconds

8h 48min 8s = 31,688 seconds

Subtract out the ground time

113,269 seconds - 31,688 seconds = 81,581 seconds in the air

divide air seconds by total seconds

81,581 / 113,269 = 0.720241195738

Convert to % by multiplying by 100 = 72.0241195738 %

;-D They had time on the ground to have a cuppa coffee.

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- Anonymous1 decade ago
41 secs, 39 mins and 22 hrs.

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- Anonymous1 decade ago
Do the math,and get back with us

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