What percent of time was spent in the air? see details?

In 1995, an aircraft set the around the-world record time for a passenger jet at 31h,27min,49s. Six refueling stops took a total of 8h, 48min,8s.

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  • 1 decade ago
    Favorite Answer

    The total number of seconds the trip took is

    31*3600+27*60+49 = 113269

    The total number of seconds spent refueling is

    8*3600+48*60+8 = 31688

    Therefore, the percentage of time spent in the air is

    100*(113269-31688)/113269 = 72.0241%.

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  • 1 decade ago

    First turn everything in to seconds, and divide.

    31h 27min 49s = 113,269 seconds

    8h 48min 8s = 31,688 seconds

    Subtract out the ground time

    113,269 seconds - 31,688 seconds = 81,581 seconds in the air

    divide air seconds by total seconds

    81,581 / 113,269 = 0.720241195738

    Convert to % by multiplying by 100 = 72.0241195738 %

    ;-D They had time on the ground to have a cuppa coffee.

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  • Anonymous
    1 decade ago

    41 secs, 39 mins and 22 hrs.

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  • garyp
    Lv 6
    1 decade ago

    Assuming jas is right about the hours

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  • Anonymous
    1 decade ago

    Do the math,and get back with us

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