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# A 0.10g spider is descending on a strand that supports it with a force of 6.6x10^-04 N.?

What is the acceleration of the spider? Ignore air resistance.

Can u please show me how to solve for it.

The answer is suppose to be 3.2m/s2 downwards.

### 2 Answers

- polloloco.rb67Lv 41 decade agoFavorite Answer
Here we will use the force equation.

That is

F = ma whre m is mass, and a is accelleration.

Draw a diagram of the spider.

The strand will have an upward force of T = 6.6x10^-04 N

Don't forget gravity. Now we need to find the downward force. This is the weight of the spider.

W = mg where w = weight, m = mass of spider, g = acceleration of gravity.

Thus

W = .10 * 9.81 = .0981 N

Thus we have two quantities.

T = 6.6x10^-04 N the upward force caused by the strand

W = .0981 the downward force caused by gravity and mass of spider

Recall our initial equation.

F = ma.

We simply need to find F since m is .10 g

F = T - W This is the upward force minus the downward force. Make sense?

thus

F = T - W = ma

F = .00066 - .0981 = .1 * a

now we solve for a

F = -.09744 = .1 * a

-0.9744 m/s^2 is your acceleration, that is .9744 m/s^2 downwards.

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- 1 decade ago
F=mass x acceleration

therefore, a=F/m

a=6.6x10^-4/0.1x10^-3

a=0.66m/s^2

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