They will meet around 76 meters from northermost point in direction of runner A (runner B will have travelled around 49 meters)
And again, same thing for the second time, treat that point as starting point, and they will meet another 76 meters in direction of A's travel (by this time, A will have made a full circle but B would not have yet)
To understand the problem, lets simplify it by saying that the speed of A is 2 KM/hr and B is 1 KM/hr. For any given time constant, A will travel twice the distance than B i.e. speed of A divided by speed of B. So when they meet, the total distance travelled by A will be double than that of A. So, if the total distance travelled is 3 KM, then 2 KM was covered by A and 1 KM was covered by B.
In this question, using the same logic, when they meet for the first time, they both have travelled for the same 'time'. We also know that they have together made a full circle, so the total distance travelled is the circumference of the circle i.e. 2*pi*radius = 2*22/7*20 = approx 125 meters.
And now to get the distance travelled by A, simply get the ratio of A's speed with is (5.31/ (5.31+3.44)) = approx 0.6068
Multiply this number by the total distance of 125 meters and you get the distance travelled by A when it meets B, which is about 76 meters.
Would have been easier to expain the answer diagramattically, but important point to note here is the ratio of speed of A and B and that they will be travelling for the same time when they meet....
· 1 decade ago