# How do you solve linear functions, f(x)=mx+b?

I should remember this from highschool but I don't. I can't learn from the book because I can't ask the book questions. I make math waaaay harder than it actually is. So hopefully someone here can help me get it to click in my brain, then all will be well.

### 9 Answers

- MitchLv 71 decade agoFavorite Answer
Linear functions aren't that difficult, but with a lousy book or teacher, it's harder than it should be.

Here's a good tutorial online=>

http://www.math.com/school/subject2/lessons/S2U4L3...

My pre-calculus teacher recommends this site:

- Login to reply the answers

- 1 decade ago
M is slope, B is the Y-intercept. You plug in the values for Y and X, then solve for whatever variable you need.

If you have two points to work with you can find your slope with the equasion (y1-y2)/(x1-x2)

That will give you a fraction which simplifies into your slope.

- Login to reply the answers

- Steve PLv 51 decade ago
y= f(x) = mx + b

m = slope of the line

b = the point where the line intercepts the Y (vertical) axis i.e. when x=0

m=slope= rise/run of the line = change is y / change in x

you need values m and b to solve the equation otherwise all points of the line are of the format ((y-b)/m,mx+b)

- Login to reply the answers

- Anonymous1 decade ago
ok. the f(x) will be the y in your first ordered pair. m is the slope. to find the slope you use y2- y1 over x2-x1. then you will multiply the slope by the x in your first order pair. then you mult. the x and the m. Then subtract that 4rm y and that gives you your b. tada you got your linear function

Source(s): algebra and geometry- Login to reply the answers

- How do you think about the answers? You can sign in to vote the answer.
- 1 decade ago
m is the slope and b is the y-intercept. make a t-chart and just start plugging in numbers for x and see what you get for y or just plug it into a graphing calculator

- Login to reply the answers

- rajLv 71 decade ago
by giving values to independent variables and finding the corresponding values of the dependent variables

- Login to reply the answers

- 1 decade ago
do u have a graphing calculator???? graph then 2nd "calc" and choose what u need.!!

- Login to reply the answers