Is this right? A line has a slope of -4 and passes thru the point (2, 3). Then an equation for that line is...

y = 3x - 10

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  • 1 decade ago
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    Can't be

    in the form "y = mx + b"

    the slope is "m"

    y = -4x + b

    3 = -4*2 + b

    11 = b

    QED

  • 1 decade ago

    You need to use the point-slope equation; (y - y1) = m(x - x1).

    Substitute -4 for m, 3 for y1 and 2 for x1.

    That gives;

    y - 3 = -4(x - 2)

    y - 3 = -4x + 8

    y = -4x + 11

  • 1 decade ago

    the standard slope form is y=mx+b, where m is the slope. in this case its -4....input your values into the equation and you get

    3 = (-4*2) + b

    3 = -8 + b

    11 = b

    so the equation would be y=-4x+11

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