VHDL 執行時的問題 (初學者)

Question

可以的話請解釋一下程式碼

初學還不太懂

要執行時要打

force ... run ....

library IEEE;

use IEEE.STD_LOGIC_1164.ALL;

use IEEE.STD_LOGIC_unsigned.all;

use IEEE.STD_LOGIC_arith.all;

entity Full_Adder is

port( Ai ,Bi ,Ci : in STD_LOGIC;

S0 ,C0 : out STD_LOGIC ) ;

end Full_Adder;

architecture test of Full_Adder is

begin

S0 <= Ai XOR Bi XOR Ci ;

C0 <= (Ai and Bi) or (Ai and Ci) or (Bi and Ci) ;

end test;

library IEEE;

use IEEE.STD_LOGIC_1164.ALL;

use IEEE.STD_LOGIC_unsigned.all;

use IEEE.STD_LOGIC_arith.all;

entity add_2bit is

port (

A, B : in STD_LOGIC_vector (1 down to 0) ;

cin : in STD_LOGIC;

s : out STD_LOGIC_vector (1 down to 0) ;

Count : out STD_LOGIC ) ;

end add_2bit ;

architecture test2 of add_2bit is

signal c1 : STD_LOGIC;

component Full_Adder

port( Ai ,Bi ,Ci : in STD_LOGIC;

S0 ,C0 : out STD_LOGIC ) ;

end component;

begin

U1 : Full_Adder port map (A(0) ,B(0) ,cin ,S(0) ,c1);

U2 : Full_Adder port map (A(1) ,B(1) ,c1 ,S(1) ,cout);

end test2 ;

Update:

剛發現錯誤

down to

要打在一起 downto

Update 2:

還有 port 裡的 Count

要改成 cout

執行時出現

"malformed time value : force"

Answer 1

Favorite Answer

打 force A xx( 00~11 )之後要按enter

再打 force B xx( 00~11 )之後也要按enter

& 打 run 100之候還是要按enter

懂了吧!!

Source(s): 自己