瘦子 asked in 科學化學 · 1 decade ago

關於IR分析的一段原文,請化學高手幫忙看一下~

In the spectra of the reference sample, the bands at 3429, 1672, 1622, and 1452 cm -1 are attributable to N– H stretching and C– O bending of urea, and the band at 450 cm-1 is attributed to the vibration mode of ZnO. This means that the reference sample remains unchanged to the original state. Comparing the spectra ground for 10 min with that of the reference, the peaks from urea molecule tend to diminish in the ground sample, although the vibration mode of ZnO remains in the spectra. Furthermore, in the spectra of 60 min ground sample, two new bands at 1500 and 1347 cm-1 are clearly observed. Although more information is needed to interpret the new bands and to correlate the appearance of the new bands with the possible bonding Zn in ZnO and N in urea, it is certainly noted that the grinding operation induces chemical changes and bonding between starting samples, compared with the unchanged state for the reference sample.

自己是翻成「在對照樣品的圖譜中,在3429、1672、1622及1452的bands是因為尿素中的N-H 鍵結和C-O 鍵結。並且在450的band是因為ZnO的振動模式。這表示對照樣品保持不變在最初的狀態。與研磨10分鐘的圖譜作對照,在研磨的樣品中,這個波峰是因為尿素分子減少而產生,雖然ZnO振動模式仍保持在圖譜中。此外,在研磨60分鐘的樣品的圖譜中,與未改變狀態的對照樣品來比較,清楚地看到在1500及1347的兩個新bands。雖然需要更多的資訊來解釋,新的bands和Zn在ZnO中及N在尿素中的可能鍵結和新的band的相關顯現,它確實在研磨操作誘導化學改變及xxxxxxx是著名的。機械化學效應在摻N進入ZnO中是有貢獻的,它將在下面的部分被討論。」

xxxx是翻不出來的,而且翻的很怪,請高手幫忙改正一下囉^_^

3 Answers

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  • 1 decade ago
    Favorite Answer

    應該要從最後一句compared with the unchanged state for the reference sample. 先翻譯,再向前翻譯.和參考樣品的不變狀態來比較,確實要被注意到的是,研磨操作會導致起始樣品之間的化學變化和鍵結作用.

    2006-04-11 13:15:47 補充:

    "研磨操作會導致起始樣品之間的化學變化和鍵結作用"應該是下面的才對!"研磨操作會導致化學變化和起始樣品之間的鍵結"

    Source(s): 自己
  • 1 decade ago

    penguiniris我是在學校圖書館系統找的paper,因為要做專題討論報告,但英文太差了翻的都不順說>_<

  • 1 decade ago

    想睡覺老兄你看ㄉ原文那來ㄚ

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