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化學翻譯成中文

請幫我翻成中文..謝了

Strategy: Keep in mind that the dipole moment of a molecule depends on both the difference in electronegativities of the elements present and its geometry. A molecule can have polar bonds (if the bonded atoms have different electronegativities), but it may not possess a dipole moment if it has a highly symmetrical geometry.

Solution: Each vertex of the hexagonal structure of benzene represents the location of a C atom. Around the ring, there is no difference in electronegativity between C atoms, so the only bonds we need to consider are the polar CCl bonds.

The molecules shown in (b) and (d) are nonpolar. Due to the high symmetry of the molecules and the equal magnitude of the bond moments, the bond moments in each molecule cancel one another. The resultant dipole moment will be zero. For the molecules shown in (a) and (c), the bond moments do not cancel and

there will be net dipole moments. The dipole moment of the molecule in (a) is larger than that in (c), because in (a) all the bond moments point in the same relative direction, reinforcing each other (see Lewis structure below). Therefore, the order of increasing dipole moments is:

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  • 1 decade ago
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    策略:

    要記住一個分子的偶極矩是視元素所表現的的電負度以及幾何結構的不同. 一個分子可以有極性共價鍵(如果鍵結的原子間有不同的電負度),但是如果他沒有呈現高度對稱的幾何結構,那它就有可能無法表現出偶極矩

    2006-03-07 01:44:35 補充:

    (對不起 最後一句是"如果他的結構呈現高度對稱...."解題:苯的六角形結構的每個頂點代表了碳原子的位置,每一個碳原子之間的電負度沒有差別,所以我們需要考慮的鍵就是有極性的C-Cl鍵了在圖(b)跟(d)所表示的分子是非極性的. 由於分子本身高度對稱且鍵矩強度相等,每個分子中的鍵矩會互相抵銷. 偶極矩的合力為0. 而在圖(a)跟(c)表示的分子,它的鍵矩沒有抵銷而會有淨偶極矩. 圖(a)的分子偶極矩大於圖(c)的分子,因為圖(a)的分子鍵矩指向相同的相對方向,強化了彼此(參考下面的路易士電子式結構). 因此,增加偶極矩的種類有:

    Source(s): 我有學過普化^^
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  • 1 decade ago

    Strategy: Keep in mind that the dipole moment of a molecule depends on both the difference in electronegativities of the elements present and its geometry. A molecule can have polar bonds (if the bonded atoms have different electronegativities), but it may not possess a dipole moment if it has a highly symmetrical geometry.(研究策略:切記一個分子的兩極會產生感應是因元素排列和幾合學在陰級電子的差異所形成的。一個分子可能有極性關連,但如果幾合對稱的狀態過於強烈,就不會有兩極產生感應的情形了。)

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