# 幾則進位換算的問題？

1.Convert the following base five numerals into base nine numerals.

2.What is wrong with the numerals 85eight and 24three?

3.Ture or False?

a. 7eight=7

b. 30four=30

c. 8nine=8eleven

d. 30five=30six

4.Convert each base ten numerals into its numeral in the base requested.

a.142 in base twelve

b.72 in base two

c.231 in base eight

5.Find the missing base.

a. 28=34

b. 28=26

c. 23twelve=43

Update:

Convert the following base five numerals into base nine numerals.

a.12five b.204five c.1322five

### 1 Answer

Rating
• R-way
Lv 4
1 decade ago
Favorite Answer

1.the following base five numerals 您沒貼呀

2.

85eight->以8為底的數 每一位應該只有從0~7∴要寫成105eight

24three->以3為底的數 每一位應該只有從0~2∴要寫成101three

3.

a.T

b.F: 30four=3*4^1+0*4^0

c.T

d.F: 30five=3*5^1+0*5^0; 30six=3*6^1+0*6^0

4.

a.142 in base twelve=(11)(10)或記成BA

b.72 in base two=1001000

c.231 in base eight=347

5.左邊固定以10為底嗎? 我先做一題不設限的囉^^

a. 28x=34y=>2x+8=3y+4且x>8,y>4,x&y為整數=>2x+4=3y且2x+4整除3(2x+1整除3)

∴從9開始代入x... 當x=10, y=8=>28ten=34eight

不過通解則不只這一組啦

b. 28=26y=>28=2y+6=>y=11∴28=26eleven

c. 23twelve=43y=>2*12+3=4y+3=>y=6∴23twelve=43six

其實像c.這題 尾數一樣而開頭成倍數 就表示底數也是呈倍數關係囉

2006-01-02 17:55:57 補充：

其實看我解了後4題之後 第一題應該不難吧 自已試試最靠得住 呵呵

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