化學題目急件,請今日解答完畢謝謝

1.Sodium azide (NaN3) is used in some automobile air bags. The impact of a collision triggers the decomposition of NaN3 as follows:

2NaN3(s)→2Na(s) + 3N2(g)

The nitrogen gas produced quickly inflates the bag between the driver and the windshield. Calculate the volume of N2 generated at 100℃ and 1atm by the decomposition of 100.0 g of NaN3. (20%)

2. .Determine the number of significant figures in these measurements: (a) 408 cm (b) 6.00 g (c) 0.0825 m

(d) 0.143 kg (e) 70000 mL (20%)

3.Describe how you would prepare 5×102 mL of 1.75 M H2SO4 solution, starting with 8.61 M stock solution of H2SO4. (20%)4.Classify these ionic compounds as soluble or insoluble:

(a) Na3(PO)4 (b) silver Nitrite (c) CaSO4 (d) CuS (e) MgCO3 (e) Zn(NO3)2 (20%)

5.The reaction between nitric oxide (NO) and Oxygen to form nitrogen dioxide (NO2) is a key step in photochemical smog formation

2 NO(g) + O2 → 2NO2(g)

(a) How many moles of NO2 are formed by the complete reaction of 2.54 mole of O2 ?

(b) How many grams of NO2 are formed by the complete reaction of 1.44 g of NO? (20%)

1 Answer

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  • Anonymous
    1 decade ago
    Best Answer

    1.鈉 azide(NaN3) 被用於一些汽車安全氣囊。 碰撞的衝擊依下列各項引起 NaN3 的分解:

    2NaN3(s)->2 Na(s) +3 N2(g)

    很快地被生產的氮瓦斯使膨脹在駕駛員和擋風玻璃之間的袋子。 計算在 NaN3 的 100.0 g 的分解旁邊的 100 ℃和 1atm 被產生的 N2 的體積. (20%)

    2. 。決定這些測量的重要數字的數字: (一) 408 cm(b) 6.00 g(c) 0.0825 m d) 0.143 公斤 (e) 70000 毫升(20%)

    3.如此描述你如何 1.75 M H2 將會 102 毫升 5 × 準備 4 解決方案,以 H2 的 8.61 M 存貨解決方案如此開始 4 。 (20%)4.分類這些離子的混合物當做溶解的或不能溶解的:

    (一) Na3(波河) 4(b)鍍以銀亞硝酸鹽 (c) CaSO4(d) CuS(e) MgCO3(e) Zn(沒有 3)2(20%)

    5.形成氮二氧化物 (沒有 2) 的在一氧化氮 (不)和氧之間的反應是光化學的煙霧形成的一個關鍵的步驟

    2 不 (g) + O2->2NO 2(g)

    (a) 多少痣沒有 2 被 O2 的 2.54個痣的完全反應形成 ?

    (b) 多少克沒有 2 被 1.44 g 的完全反應形成? (20%)

    Source(s): 我= =
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