Anonymous
Anonymous asked in 電腦與網際網路程式設計 · 1 decade ago

如何寫一支計算天數間的PHP程式

如何寫一支計算天數間的PHP程式,如2005/1/3~2006/8/25是幾天

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  • 1 decade ago
    Best Answer

    function datediff($interval, $datefrom, $dateto, $using_timestamps = false) {

    /*

    $interval can be:

    yyyy - Number of full years

    q - Number of full quarters

    m - Number of full months

    y - Difference between day numbers

    (eg 1st Jan 2004 is "1", the first day. 2nd Feb 2003 is "33". The datediff is "-32".)

    d - Number of full days

    w - Number of full weekdays

    ww - Number of full weeks

    h - Number of full hours

    n - Number of full minutes

    s - Number of full seconds (default)

    */

    if (!$using_timestamps) {

    $datefrom = strtotime($datefrom, 0);

    $dateto = strtotime($dateto, 0);

    } // End of if (!$using_timestamps)

    $difference = $dateto - $datefrom; // Difference in seconds

    switch($interval) {

    case 'yyyy': // Number of full years

    $years_difference = floor($difference / 31536000);

    if (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom), date("j", $datefrom), date("Y", $datefrom)+$years_difference) > $dateto) {

    $years_difference--;

    }

    if (mktime(date("H", $dateto), date("i", $dateto), date("s", $dateto), date("n", $dateto), date("j", $dateto), date("Y", $dateto)-($years_difference+1)) > $datefrom) {

    $years_difference++;

    }

    $datediff = $years_difference;

    break;

    case "q": // Number of full quarters

    $quarters_difference = floor($difference / 8035200);

    while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($quarters_difference*3), date("j", $dateto), date("Y", $datefrom)) < $dateto) {

    $months_difference++;

    }

    $quarters_difference--;

    $datediff = $quarters_difference;

    break;

    case "m": // Number of full months

    $months_difference = floor($difference / 2678400);

    while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($months_difference), date("j", $dateto), date("Y", $datefrom)) < $dateto) {

    $months_difference++;

    }

    $months_difference--;

    $datediff = $months_difference;

    break;

    case 'y': // Difference between day numbers

    $datediff = date("z", $dateto) - date("z", $datefrom);

    break;

    case "d": // Number of full days

    $datediff = floor($difference / 86400);

    break;

    case "w": // Number of full weekdays

    $days_difference = floor($difference / 86400);

    $weeks_difference = floor($days_difference / 7); // Complete weeks

    $first_day = date("w", $datefrom);

    $days_remainder = floor($days_difference % 7);

    $odd_days = $first_day + $days_remainder; // Do we have a Saturday or Sunday in the remainder?

    if ($odd_days > 7) { // Sunday

    $days_remainder--;

    }

    if ($odd_days > 6) { // Saturday

    $days_remainder--;

    }

    $datediff = ($weeks_difference * 5) + $days_remainder;

    break;

    case "ww": // Number of full weeks

    $datediff = floor($difference / 604800);

    break;

    case "h": // Number of full hours

    $datediff = floor($difference / 3600);

    break;

    case "n": // Number of full minutes

    $datediff = floor($difference / 60);

    break;

    default: // Number of full seconds (default)

    $datediff = $difference;

    break;

    } // End of switch($interval)

    return $datediff;

    } // End of function datediff($interval, $datefrom, $dateto, $using_timestamps = false)

    例如2005/1/3~2006/8/25 datediff('d', '2005/1/3', '2006/8/25', false)

    Source(s): 網路找來的Code
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