• Why are your so dolorous today?

    Best answer: Didnt get enough sleep
    Best answer: Didnt get enough sleep
    4 answers · 1 week ago
  • What are the Moles of O?

    Best answer: O represents single atoms of oxygen. So, 1 mole of oxygen would be 6.022X10^23 individual oxygen atoms, and would have a mass of 16.00 grams. Normally, when the word "oxygen" is used, it refers to O2 molecules, the stable form of oxygen. One mole of O2 would consist of 6.022X10^23 molecules of O2, and... show more
    Best answer: O represents single atoms of oxygen. So, 1 mole of oxygen would be 6.022X10^23 individual oxygen atoms, and would have a mass of 16.00 grams.

    Normally, when the word "oxygen" is used, it refers to O2 molecules, the stable form of oxygen. One mole of O2 would consist of 6.022X10^23 molecules of O2, and would have a mass of 32.00 grams.
    6 answers · 1 week ago
  • PLEASE HELP! I've got some doubts about moles (CHEMISTRY)?
  • How to dispose of chlorosulphonic acid?

    5 answers · 1 week ago
  • Will Mountain Dew dissolve gum?

    Best answer: Gum is rubber. It used to be natural rubber, now it is synthetic mostly. Which means it is a polymer and it needs a chemical that will break down polymers to dissolve it. Of which there are a few but since they aren't household chemicals I will decline to name them here. But no, soda won't do it.
    Best answer: Gum is rubber. It used to be natural rubber, now it is synthetic mostly. Which means it is a polymer and it needs a chemical that will break down polymers to dissolve it. Of which there are a few but since they aren't household chemicals I will decline to name them here. But no, soda won't do it.
    6 answers · 2 weeks ago
  • What is the correct answer to this chemistry multiple choice question?

    A 2.57 g sample Of an unknown substance is composed of 1.61 g of copper and .96 g of fluorine. The empirical formula of the sample is A) Cu2F B) Cu2F2 C) CuF2 D) CuF
    A 2.57 g sample Of an unknown substance is composed of 1.61 g of copper and .96 g of fluorine. The empirical formula of the sample is A) Cu2F B) Cu2F2 C) CuF2 D) CuF
    5 answers · 2 weeks ago
  • Why is water unstable?

    4 answers · 2 weeks ago
  • In school I've been trying to make a lighter backpack.Does anyone know a chemical or option to make it work?* It Should Not Be Complicated?

    Best answer: The lightest metal that is available and does not cost a fortune is aluminum. Most of the frames made today are out of aluminum so I doubt you would be able to cut off more than a ounce or two changing that around some. The fabric could be rip stop nylon which is tough and light weight, not much you can do... show more
    Best answer: The lightest metal that is available and does not cost a fortune is aluminum. Most of the frames made today are out of aluminum so I doubt you would be able to cut off more than a ounce or two changing that around some. The fabric could be rip stop nylon which is tough and light weight, not much you can do there. NOW, where you can really cut weight is figuring out how to make the shoulder straps and hip harness lighter weight without losing any of the padding. Keep in mind that no matter how light you make it, if you start throwing in books and etc the weight of the backpack is not really going to matter.
    5 answers · 2 weeks ago
  • Need help with chemistry?

    Best answer: You can read the balanced equation as:
    N2(g) +3H2(gas)→ 2NH3(g)
    1mol N2 molecules reacts with 3 mol H2 molecules to produce 2 mol of NH3 molecules
    Now you can answer the question:
    how many moles of nitrogen molecules are used to produce two moles of ammonia molecules
    Answer: 1 mol N2 molecules
    Best answer: You can read the balanced equation as:
    N2(g) +3H2(gas)→ 2NH3(g)
    1mol N2 molecules reacts with 3 mol H2 molecules to produce 2 mol of NH3 molecules
    Now you can answer the question:
    how many moles of nitrogen molecules are used to produce two moles of ammonia molecules
    Answer: 1 mol N2 molecules
    5 answers · 2 weeks ago
  • Chemistry titration help!!!!?

    If you wanted to neutralize 4.00g NaOH, what volume (1) of 1.0 M HCl would you need?
    If you wanted to neutralize 4.00g NaOH, what volume (1) of 1.0 M HCl would you need?
    4 answers · 2 weeks ago
  • HELP WITH GEN CHEM 2, Please show work?

    the reaction CH3NC (g)--->CH3CN (g) has the experimental rate law : Rate=k[CH3NC] If the reaction has a half of 20.0 seconds, how long will it take for the concentration of CH3Nc to go from 2.00 M to 0.250M
    the reaction CH3NC (g)--->CH3CN (g) has the experimental rate law : Rate=k[CH3NC] If the reaction has a half of 20.0 seconds, how long will it take for the concentration of CH3Nc to go from 2.00 M to 0.250M
    4 answers · 2 weeks ago
  • How many chlorine atoms are present in 0.778 moles of Cl2?

    I keep getting the answer 4.68X10^23 but my teacher s answer on the study guide is 9.37x10^23. (0.778mol)(6.022x10^23) is the equation I m using to answer.
    I keep getting the answer 4.68X10^23 but my teacher s answer on the study guide is 9.37x10^23. (0.778mol)(6.022x10^23) is the equation I m using to answer.
    6 answers · 3 weeks ago
  • In Boyle’s Law, can an answer be determined if two values are not stated?

    Best answer: Not really. Not if all you have is the one relationship. P1*V1=P2*V2 has four unknowns. This requires four simultaneous equations (relationships that state new facts and not just a re-write of that same relationship). Normally, when we say a "known", that is an equation: P1=7 kbar. So, you would need... show more
    Best answer: Not really. Not if all you have is the one relationship. P1*V1=P2*V2 has four unknowns. This requires four simultaneous equations (relationships that state new facts and not just a re-write of that same relationship). Normally, when we say a "known", that is an equation: P1=7 kbar. So, you would need three knowns (three such equations) to be able to solve the fourth.

    In essence, sometimes the information is there but you have not seen how it provides an additional equation that can be used to solve the starting problem. If you only know two values, all that you can know is a ratio that applies to the other two unknown values. You have a line that represents all possible solutions, not a single point. You require one more relationship that defines something in addition to that linear relationship.
    5 answers · 2 weeks ago
  • Chemistry help wanted!?

    Best answer: a. Ar (Z = 18) : 1s² 2s² 2d⁶ 3s² 3p⁶
    b. Cl (Z = 17) : 1s² 2s² 2d⁶ 3s² 3p⁵
    c. S (Z = 16) : 1s² 2s² 2d⁶ 3s² 3p⁴
    d. P³⁻ (Z = 15) : 1s² 2s² 2d⁶ 3s² 3p⁶

    The answers : b and c
    Best answer: a. Ar (Z = 18) : 1s² 2s² 2d⁶ 3s² 3p⁶
    b. Cl (Z = 17) : 1s² 2s² 2d⁶ 3s² 3p⁵
    c. S (Z = 16) : 1s² 2s² 2d⁶ 3s² 3p⁴
    d. P³⁻ (Z = 15) : 1s² 2s² 2d⁶ 3s² 3p⁶

    The answers : b and c
    4 answers · 2 weeks ago