A heavy sled is being pulled by two people as shown in the figure. The coefficient of static friction between the sled and the ground is μs = 0.619, the coefficient of kinetic friction is μk = 0.405, and the combined mass of the sled and its load is m = 306 kg. The ropes are separated by an angle φ = 24°, and they make an angle θ with the horizontal.
Assuming both ropes pull equally hard, what is the minimum rope tension required to get the sled moving?
I'm having a hard time finding the θ angle, and then what process to solve.
A step by step, with symbol equations, to help me understand would be appreciated. The "Figure" is of two people holding a bar that has two ropes that meet on the ends then meet at the sled at the baseon a single point. the angle going up to the people's hands is the (theta) angle and the 24(degree) angle is the one between the ropes