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# Consider the line that passes through the point (3, -2) and has a slope of 2.?

Consider the line that passes through the point (3, -2) and has a slope of 2.

Part 1: Write the equation of this line using point-slope form. (2 points)
Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. (2 points)
Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work. (2 points) plz hlp i rlly need it thanksss! =D
by Bif
Member since:
November 15, 2010
Total points:
5,880 (Level 5)

## Best Answer - Chosen by Voters

Part 1: Plug into point slope formula: y-y1=m(x-x1)
y+2=2(x-3)

Part 2: Solve for y
y+2=2x-6
y=2x-8

Part 3: Rearrange to standard form
2x-y-8=0
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• Member since:
May 11, 2010
Total points:
28,917 (Level 7)
The line passes through the point (3,-2), and has a slope of 2

1. The formula for the point-slope form is given by y - y1 = m(x - x1), where the point is (x1,y1) and the slope is "m":

y - (-2) = 2(x - 3)

Simplifying:

y + 2 = 2(x - 3)

2. Slope-intercept form is given by y = mx + b, where "m" is the slope and "b" is the y-intercept:

y + 2 = 2(x - 3)

y + 2 = 2x - 6

y = 2x - 8

3. Standard form is given by Ax + By = C, where A, B, and C are constants:

y = 2x - 8

y - 2x = -8

In this case, A = 1, B = -2, and C = -8.
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• by Edward
Member since:
September 25, 2010
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1,383 (Level 3)
y-y1=m(x-x1) m= slope. y+2=2(x-3) now set it up in slope intercept form by multiplying the 2 to the x and the negative 3 to get 2x-6. now subtract the 2 from the left side of the equation. You now have 2x-8.
• Member since:
September 15, 2010
Total points:
987 (Level 2)
y - (-2) = 2(x-3)

y + 2 = 2x-6
y = 2x - 6 -2
y = 2x-8