A tiger leaps horizontally from a 6.1 m high rock with a speed of 3.9 m/s. How far from the base of the rock w?

Question

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How far from the base of the rock will she land?***

Answer 1

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vertical component
s=ut+1/2at^2
6.1=0+1/2x9.8x t^2
t^2=6.1/4.9=1.25
t=under root1.25=1.12s
horizontal component
dist covered in 1.12s
3.9x1.12=4.368m

Answer 2

A tigress.
Time to drop 6.1m = sqrt. (2h/g), = 1.116 secs.
(1.116 x 3.9) = 4.35m. from the base of the rock.