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# Find an equation in standard form for the line described?

Has x intercept 6 and y intercept 4

I don't want the answer, I want to know how to solve it. I get to y= m6 + 4 and I have no idea how to solve that.

4 years ago

by Justin
Member since:
March 06, 2010
Total points:
645 (Level 2)

So we first take a look at the givens:
x=6 when y=0 (since x-intercept is 6)
x=0 when y=4 (since y-intercept is 4)

Since we have two points of this line, we can find its slope.
We get a slope of (4-0)/(0-6) or -4/6.

Using the slope-intercept form:
y=(-4/6)x+4

We can turn this into standard form by moving all the terms to one side
(-4/6)x-y+4=0
-4x-6y+24=0
4x+6y-24=0
2x+3y-12=0

This equation in standard form is:
2x+3y-12=0

P.S.
The reason why your way doesn't work is because the slope-intercept form you're using has to use x and y coordinates from one specific point and you're using information from two different points. The y intercept is a different spot from the x intercept, so the way you're doing it won't give you an answer.

P.P.S. Why am I getting thumbed down? I did everything right. D:

I hope this helped! :)
• 3 people rated this as good
You got thumbs down because standard for is Ax+By=C
hahahha but thank you :) This helped a lot.
lolk thnx xD

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• Member since:
January 09, 2008
Total points:
13,334 (Level 6)
If the line has x-intercept 6, then it passes through the point (6, 0).
The y-intercept is 4, so it passes through the point (0, 4).

From these two points, you can find the slope of the line.

Slope (m) = (y2 - y1) / (x2 - x1)
= (4 - 0) / (0 - 6)
= 4 / -6 = -4/ 6 = -2/3.

The y-intercept is 4, so c = 4.

The equation for a straight line is y = mx + c, where m is the slope, and c is the y-intercept.

So, the equation of this line is y = -2x/3 + 4.

I hope that helps. :)

ILoveMaths07.
• by Unknown
Member since:
April 07, 2010
Total points:
9,928 (Level 5)
So the line goes through (6,0) and (0,4)

The equation for the line is

y = mx + b

Where m is the slope and b is the y intercept;

Slope = (y2 - y1)/(x2 - x1)
Slope = (0 - 4)/(6 - 0)
Slope = -4/6

The slope is -2/3 and the y intercept is 4, so:

y = -2/3x + 4
• 1 person rated this as good
• Member since:
February 11, 2006
Total points:
11,719 (Level 6)
The slope is 4/6 or 2/3 and the y-intercept is 4.
So the equation in slope-intercept form is
y = (2/3)x + 4 Now, put it in standard form.

-(2/3)x + y = 4 Multiply by -3 to get
2x -3y = -12
• Member since:
April 04, 2008
Total points:
794 (Level 2)
2x+3y=12
• 1 person rated this as good