If the line has x-intercept 6, then it passes through the point (6, 0).
The y-intercept is 4, so it passes through the point (0, 4).
From these two points, you can find the slope of the line.
Slope (m) = (y2 - y1) / (x2 - x1)
= (4 - 0) / (0 - 6)
= 4 / -6 = -4/ 6 = -2/3.
The y-intercept is 4, so c = 4.
The equation for a straight line is y = mx + c, where m is the slope, and c is the y-intercept.
So, the equation of this line is y = -2x/3 + 4.
I hope that helps. :)