How to Write a C++ program to Calculate the Cost of This?

Question

Write a c++ program to calculate the cost of a visit to a gas station. The program should ask the user whether he or she wants regular (2.629$ per gallon) or premium (2.979$ per gallon) of gasoline, whether or not a car wash is desired. Of course the program must also ask how many gallons it took to fill the tank. Then the program should calculate the cost of the gas and the total cost including a car wash if there was one. Help me please, Thank You!

Answer 1

Best Answer - Chosen by Asker

double x, g;
char y;

cout<<"Press 1 for regular 2 for premium."<<endl;
cin>>x;
cout<<"would you like a car wash? y/n?"<<endl;
cin>>y;
cout<<"How many gallons to fill your tank?"<<endl;
cin>>g;

if ( x = 1 ) {
x = g * 2.629;
} else {
x = g * 2.979;

if ( y = "y" ) {
x = x + whatever car wash costs
}

cout<<"your total is: "<<x<<endl;

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Asker's Comment:

Thank You!

Answer 2

#include<iostream.h>
#include<conio.h>
main()
{
int type;
float typecost[]={2.629,2.979};
float carwashcost=0;
int carwash;
int noofgallons;
float totalcost;

cout<<"Enter Type:\n1-Regular (2.629$ per gallon)\n2-Premium (2.979$ per gallon)\n";
cin>>type;
cout<<"Number of gallons:";
cin>>noofgallons;
cout<<"Desire Car Wash:\n1-Yes \n2-No\n";
cin>>carwash;
if (carwash==1)
{
cout<<"Cost for Car Wash:\n";
cin>>carwashcost;
}
totalcost = (typecost[type-1]*noofgallons) + carwashcost;
cout<<"Total cost for gas is "<<(typecost[type-1]*noofgallons)<<" and total cost for the service is "<<totalcost;
getche();
}