5x-6y=19, 6x+5y=-30 are these parallel or perpendicular or neither?

Answer 1

Best Answer - Chosen by Voters

5x-6y=19
-6y = -5x+19
y = (5/6)x-(19/6)
Since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m1= 5/6

6x+5y=-30
5y = -6x+30
y = (-6/5)x+6
Similarily, since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m2= -6/5

Since m1*m2 = (5/6)*(-6/5) = -1,then these two lines are perpendicular to each other.

Answer 2

perpendicular.

5x-6y=19
-6y=-5x+19
y= (5/6)x +19

m = 5/6

6x+5y=-30
5y=-6x-30
y=(-6/5)x -30

m=-6/5

5/6 & -6/5 are negative reciprocals therefore the lines are perpendicular

Answer 3

5x-6y=19, 6x+5y=-30

-6y=-5x+19, 5y=-6x-30
y=(5/6)x-(19/6), y=(-6/5)x-6

Parallel is same slope, perpendicular is opposite reciprocals. Perpendicular?

Answer 4

Slope of line ax+by+c=0 is = -a/b.

Slope of first line is m1 = 5/6

Slope of second line is m2 = - 6/5.

Their product is m1x m2 = -1.

So lines are PERPENDICULAR...............Ans.

Answer 5

Perpendicular. The slopes are reciprocals of each other. -A/B = 5/6 and -6/5

Answer 6

Dont you have the equtations to figure these out?
M= (x+x, y+y) Divided by two.
Slope = Rise over run