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## Resolved Question

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# 5x-6y=19, 6x+5y=-30 are these parallel or perpendicular or neither?

by gab BB
Member since:
June 13, 2007
Total points:
15,050 (Level 6)

## Best Answer - Chosen by Voters

5x-6y=19
-6y = -5x+19
y = (5/6)x-(19/6)
Since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m1= 5/6

6x+5y=-30
5y = -6x+30
y = (-6/5)x+6
Similarily, since this line is expressed in the standard linear form of y=mx+b where m is the slope, so the slope of this line = m2= -6/5

Since m1*m2 = (5/6)*(-6/5) = -1,then these two lines are perpendicular to each other.

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• Member since:
April 04, 2006
Total points:
534 (Level 2)
perpendicular.

5x-6y=19
-6y=-5x+19
y= (5/6)x +19

m = 5/6

6x+5y=-30
5y=-6x-30
y=(-6/5)x -30

m=-6/5

5/6 & -6/5 are negative reciprocals therefore the lines are perpendicular
• by kyle h
Member since:
November 05, 2008
Total points:
427 (Level 2)
5x-6y=19, 6x+5y=-30

-6y=-5x+19, 5y=-6x-30
y=(5/6)x-(19/6), y=(-6/5)x-6

Parallel is same slope, perpendicular is opposite reciprocals. Perpendicular?
• by Hemant
Member since:
August 16, 2009
Total points:
117,142 (Level 7)
Slope of line ax+by+c=0 is = -a/b.

Slope of first line is m1 = 5/6

Slope of second line is m2 = - 6/5.

Their product is m1x m2 = -1.

So lines are PERPENDICULAR...............Ans.
• by яα¢нαєℓ
Member since:
April 08, 2009
Total points:
2,037 (Level 3)
Perpendicular. The slopes are reciprocals of each other. -A/B = 5/6 and -6/5
• Member since:
August 18, 2009
Total points:
158 (Level 1)
Dont you have the equtations to figure these out?
M= (x+x, y+y) Divided by two.
Slope = Rise over run