Simplify -x3 + 3x2 + 4 + (x2 - 5x - 1).?

Answer 1

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-x3 + 3x2 + 4 + (x2 - 5x - 1).?
= -x^3 + 3x^2 + 4 + x^2 - 5x -1
= -x^3 + 4x^2 - 5x +3

Source(s):

ge

Answer 2

-x3 + 3x2 + 4 + (x2 - 5x - 1)

I'm assuming that the numbers after the letters are exponents
...3......2.........2
-x +3x +4+(x -5x-1)

you can remove the () when there is a + before it
...3.....2.......2
-x +3x +4+x -5x-1

..............................2.......…
you can add the x to the 3x
...3......2
-x +4x +4-5x-1

you can add the 4 and the -1
...3....2
-x +4x +3-5x
The equation above would be a Jr. High answer



Assuming that this equation is equal to 0 you can find the value of x.
...3....2
-x +4x +3-5x=0

rearrange the equation so it's easier to work with
...3......2
-x +4x -5x+3=0

divide the first 3 values by x
......2
x(-x +4x-5)+3=0

Up to this point I am a little rusty so I'm not sure how to finish it, but I know it is possible. First try to make a binomial, but if that doesn't work you will have to use the quadratic equation.

Source(s):

Straight A math student

Answer 3

-x³ + 3x² + 4 + (x² - 5x - 1)
-x³ + 3x² + 4 + x² - 5x - 1
-x³ + 4x² - 5x + 3

Answer 4

- x^3 + 3x^2 + 4 + x^2 - 5x - 1

Combine like terms

- x^3 + 4x^2 + 3

Answer 5

-x3 + 3x2 + 4 + (x2 - 5x - 1)
= -x^3 + 4x^2 - 5x +3

Answer 6

-x^3 + 4x^2 - 5x + 3

Answer 7

I'm doing the samthing in 7th grade math.....

-16x + 4