Use the elimination method to solve the following system of equations ?

Question

2x+5y= -22
10x+3y=22

Answer 1

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2x+5y= -22
10x+3y=22

multiply both sides of the first equation by -5 and add to the second
that will eliminate x

-10x -25y = 110
10x + 3y = 22
-22y = 132
y = -6

Substituting (-6) for y in either equation:
2x + 5(-6) = -22
2x = 8
x = 4

10x + 3(-6) = 22
10x = 40
x = 4

so the solution to the system is (4,-6)

Answer 2

Multiply the first equation by 5 and then subtract from second equation.we get 10x + 25y = -110
- (10x + 3y = 22)

that is 22y = 88
that is y = -6

For x we substiute the value of y in 2x + 5y = -22
2x - 30 = -22
2x = -22 + 30 = 8
x = 4

Answer 3

Let us eliminate y
Multiply equation (1) by -3 and equation (2) by 5
-6x-15y=66
50x+15y=110
Add:
44x = 176
x= 176/44 =4
plug this x into equation (1)
2(4) + 5y = -22
8 +5y =-22
5y =-30
y =-6

x=4, y=-6

Answer 4

Multiply the first equation by 5:
10x + 25y = -110

Now subtract the second equation from the first. This eliminates x, leaving you with:
22y = -132
y = -6

Plug that back in to either equation, and you find that x = 4

Answer 5

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