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# Use the elimination method to solve the following system of equations ?

2x+5y= -22
10x+3y=22
Member since:
September 13, 2008
Total points:
3,469 (Level 4)

## Best Answer - Chosen by Voters

2x+5y= -22
10x+3y=22

multiply both sides of the first equation by -5 and add to the second
that will eliminate x

-10x -25y = 110
10x + 3y = 22
-22y = 132
y = -6

Substituting (-6) for y in either equation:
2x + 5(-6) = -22
2x = 8
x = 4

10x + 3(-6) = 22
10x = 40
x = 4

so the solution to the system is (4,-6)
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• Member since:
October 17, 2006
Total points:
76 (Level 1)
Multiply the first equation by 5 and then subtract from second equation.we get 10x + 25y = -110
- (10x + 3y = 22)

that is 22y = 88
that is y = -6

For x we substiute the value of y in 2x + 5y = -22
2x - 30 = -22
2x = -22 + 30 = 8
x = 4
• by cidyah
Member since:
February 24, 2007
Total points:
264,920 (Level 7)
Let us eliminate y
Multiply equation (1) by -3 and equation (2) by 5
-6x-15y=66
50x+15y=110
44x = 176
x= 176/44 =4
plug this x into equation (1)
2(4) + 5y = -22
8 +5y =-22
5y =-30
y =-6

x=4, y=-6
• by Jason
Member since:
August 07, 2008
Total points:
974 (Level 2)
Multiply the first equation by 5:
10x + 25y = -110

Now subtract the second equation from the first. This eliminates x, leaving you with:
22y = -132
y = -6

Plug that back in to either equation, and you find that x = 4
• by werrdna
Member since:
January 28, 2009
Total points:
217 (Level 1)
why do you want the answer

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