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# Physics help the decay of 235U?

235U +1 n = 98Mo + unknown isotope + 2 n + 4e- + 4 1stgen anitleptons

Sorry couldnt write symbol for 1st generation antilepton.

but my question is, in the above radioactive decay what would be the unknown isotope.

i calculated it to be 132 Xe is this correct ?

144 n and 92p on the left.

on the right there are 56n in Mo 2n free and 4n converted to 4p via beta- minus decay, this leaves 82n

on the rigth there are 42p in Mo.
which leaves 50p, but 4 extra p converted from n in beta-minus decay.
which give us 54p.

so 136Xe

5 years ago

by El Cid
Member since:
January 17, 2007
Total points:
19,970 (Level 6)

not sure how the answer is calculated, but thanks anyway

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• Member since:
September 03, 2007
Total points:
44,242 (Level 7)
Total mass of 236 (235 + 1) on left hand side.

So, total mass on right hand side =

236 = 98 + 2 (the neutrons) + X (the electrons and neutrinos have negligible mass)

I reckon X has a mass of 136.

Looking at proton numbers, U = 92, Mo = 42, so X should = 50, which means it's Sn

Does 136Sn look right?
• by Pete WG
Member since:
February 07, 2007
Total points:
2,658 (Level 4)
Am I missing something here? Fission itself does not, to my knowledge, produce antileptons - only neutrons, gamma photons and daughter nuclei.The neutron-rich daughter nuclei,however, decay by beta emission. This produces one lepton (an electron, or beta particle) and one antilepton ( an electron antineutrino).

### Source(s):

Former nuclear engineer.