A média aritmetica de um conjunto de 11 numeros é 45. Se o numero 8 for retirado do conjunto, a media dos numeros restantes será de:
R: 48,7
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A media aritmetica eh a soma do "valor" dos elementos, dividido pelo numero de elementos (11).
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10+e11)/1…
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10+e11)=4…
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10+e11)=4…
um dos elementos eh igual a 8, retirando um dos elementos os restantes serao 10
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10)=495-8
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10)=487
A media aritmetica dos 10 elementos serah
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10)=487/1…
487/10= 48,7
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10+e11)/1…
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10+e11)=4…
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10+e11)=4…
um dos elementos eh igual a 8, retirando um dos elementos os restantes serao 10
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10)=495-8
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10)=487
A media aritmetica dos 10 elementos serah
(e1+e2+e3+e4+e5+e6+e7+e8+e9+e10)=487/1…
487/10= 48,7
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