Find the integral from 10 to 13 of 2xdx?

Question

ba-dum-pssh.

Additional Details

I guess my sense of humor is too childish.
"ba-dum-pssh" the sound of percussion after telling a real zinger.

Answer 1

Best Answer - Chosen by Asker

69

Asker's Rating:

Asker's Comment:

I thought it was funny.

Answer 2

integral of 2xdx is x^2.

Within the limits of 10 and 13, substitute x as 13 and 10 then subtract both. Thus,

13^2 - 10^ 2 = 169 - 100
= 69

Answer 3

69

Answer 4

The integral of 2x is x^2+c and putting the limits we get
13*13-10*10=69

Answer 5

Int 2x dx
=x^2
Inserting the limits
169-100
=69

Answer 6

Int(2x) = x^2 {13, 10}

13^2 - 10^2 = 69

Answer 7

Find the primitive of 2x, i.e. what do I have to differentiate to get 2x?
The answer obviously is x^2. (General rule for primitive of x^n is (x^(n+1))/(n+1) provided n is not -1)

Then you sub each of the boundary values (10 and 13) in this primitive and subtract. i.e. your answer is
13^2 - 10^2

Strictly speaking, the primitive of 2x is x^2 + C, where C is some arbitrary constant, because the derivative of a constant is zero. However, when you're going to substitute and subtract there's no point in including C, because
(13^2 + C -(10^2 + C)) is still 13^2 - 10^2.

Answer 8

Integral of 2x dx = x^2
From x = 10 to x = 13,
the area is 13^2 - 10^2,
= 169 - 100
= 69

Answer 9

=2(X^2)|10,13=2*81=162